Inverting a dictionary in Python

Introduction

Inverting a dictionary means swapping its keys and values. This helps when you want to look up original keys by their values.

You have a dictionary of country codes to country names and want to find the code by name.

You store usernames as keys and user IDs as values, and want to find usernames by ID.

You have a mapping of product IDs to product names and want to find the ID by name.

Syntax

Python

inverted_dict = {value: key for key, value in original_dict.items()}

This creates a new dictionary where each original value becomes a key, and each original key becomes a value.

Make sure original values are unique and hashable, or you may lose data or get errors.

Examples

Simple example swapping letters and numbers.

Python

original = {'a': 1, 'b': 2}
inverted = {v: k for k, v in original.items()}
print(inverted)

Inverts a dictionary of foods to their types.

Python

original = {'apple': 'fruit', 'carrot': 'vegetable'}
inverted = {v: k for k, v in original.items()}
print(inverted)

If values repeat, the last key wins in the inverted dictionary.

Python

original = {'x': 10, 'y': 10}
inverted = {v: k for k, v in original.items()}
print(inverted)

Sample Program

This program inverts a color-to-hex dictionary so you can find the color name by its hex code.

Python

original_dict = {'red': '#FF0000', 'green': '#00FF00', 'blue': '#0000FF'}
inverted_dict = {value: key for key, value in original_dict.items()}
print('Original:', original_dict)
print('Inverted:', inverted_dict)

Important Notes

If original values are not unique, some keys will be lost in the inverted dictionary.

Values must be hashable (like strings, numbers, or tuples) to be dictionary keys.

Summary

Inverting swaps keys and values in a dictionary.

Use dictionary comprehension with .items() to invert.

Be careful with duplicate values and unhashable types.

Practice

1.

What does inverting a dictionary mean in Python?

easy

A. Sorting the dictionary by keys

B. Swapping keys and values so values become keys and keys become values

C. Removing duplicate keys from the dictionary

D. Changing all values to uppercase strings

Solution

1. Step 1: Understand dictionary structure

   A dictionary has keys and values paired together.

2. Step 2: Define inverting

   Inverting means swapping each key with its value, so keys become values and values become keys.

3. Final Answer:

   Swapping keys and values so values become keys and keys become values -> Option B

4. Quick Check:

   Inverting = swapping keys and values [OK]

Hint: Invert means swap keys and values in a dictionary [OK]

Common Mistakes:

• Thinking inverting sorts the dictionary
• Confusing inverting with removing duplicates
• Assuming values become uppercase strings

2.

Which of the following is the correct syntax to invert a dictionary d using dictionary comprehension?

easy

A. {k: v for k, v in d}

B. {k: v for v, k in d.items()}

C. {d[v]: d[k] for k, v in d.items()}

D. {v: k for k, v in d.items()}

Solution

1. Step 1: Recall dictionary comprehension syntax

   It uses {new_key: new_value for key, value in dict.items()}.

2. Step 2: Swap keys and values correctly

   To invert, new_key = value and new_value = key, so use {v: k for k, v in d.items()}.

3. Final Answer:

   {v: k for k, v in d.items()} -> Option D

4. Quick Check:

   Correct syntax = {v: k for k, v in d.items()} [OK]

Hint: Use {v: k for k, v in d.items()} to invert dictionary [OK]

Common Mistakes:

• Swapping variables incorrectly in comprehension
• Using d[v] or d[k] inside comprehension wrongly
• Forgetting to call .items() on dictionary

3.

What is the output of this code?

original = {'a': 1, 'b': 2, 'c': 3}
inverted = {v: k for k, v in original.items()}
print(inverted)

medium

A. {1: 'a', 2: 'b', 3: 'c'}

B. {'a': 1, 'b': 2, 'c': 3}

C. {'1': 'a', '2': 'b', '3': 'c'}

D. Error: unhashable type

Solution

1. Step 1: Understand original dictionary

   Keys are 'a', 'b', 'c' and values are 1, 2, 3.

2. Step 2: Invert dictionary using comprehension

   Swapping keys and values gives keys 1, 2, 3 and values 'a', 'b', 'c'.

3. Final Answer:

   {1: 'a', 2: 'b', 3: 'c'} -> Option A

4. Quick Check:

   Inverted dict = {1: 'a', 2: 'b', 3: 'c'} [OK]

Hint: Invert swaps keys and values exactly as pairs [OK]

Common Mistakes:

• Expecting original dictionary output
• Confusing string and integer keys
• Thinking inversion causes error here

4.

What is wrong with this code to invert a dictionary?

d = {'x': 10, 'y': 10}
inverted = {v: k for k, v in d.items()}
print(inverted)

medium

A. It will keep only one key for duplicate values

B. It will invert correctly with no issues

C. It will raise a TypeError

D. It will raise a KeyError

Solution

1. Step 1: Identify duplicate values in dictionary

   Both 'x' and 'y' have value 10, which is duplicated.

2. Step 2: Understand dictionary key uniqueness

   When inverting, keys must be unique, so only one key-value pair with key 10 remains.

3. Final Answer:

   It will keep only one key for duplicate values -> Option A

4. Quick Check:

   Duplicate values cause lost keys in inversion [OK]

Hint: Duplicate values become keys, only last key kept [OK]

Common Mistakes:

• Expecting all keys preserved after inversion
• Thinking it raises an error for duplicates
• Ignoring key uniqueness in dictionaries

5.

Given a dictionary with possible duplicate values, how can you invert it so each value maps to a list of keys that had that value?

original = {'a': 1, 'b': 2, 'c': 1}

Which code correctly inverts it to {1: ['a', 'c'], 2: ['b']}?

hard

A. inverted = {v: [k] for k, v in original.items()}

B. inverted = {v: k for k, v in original.items()}

C. inverted = {}
for k, v in original.items():
inverted.setdefault(v, []).append(k)

D. inverted = {v: k for v, k in original.items()}

Solution

1. Step 1: Understand problem with duplicates

   Simple inversion loses keys when values repeat, so we need lists to hold multiple keys.

2. Step 2: Use setdefault and append to collect keys

   Loop through items, for each value use setdefault to create list if missing, then append key.

3. Step 3: Check code correctness

   inverted = {} for k, v in original.items(): inverted.setdefault(v, []).append(k) uses this approach correctly, building lists of keys per value.

4. Final Answer:

   inverted = {} for k, v in original.items(): inverted.setdefault(v, []).append(k) -> Option C

5. Quick Check:

   Use setdefault + append to group keys by value [OK]

Hint: Use setdefault with append to group keys by value [OK]

Common Mistakes:

• Using simple comprehension losing duplicate keys
• Swapping variables incorrectly in comprehension
• Expecting one-to-one inversion with duplicates