Why dictionaries are used in Python - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a dictionary with keys as names and values as ages.

Python

ages = {'Alice': 25, 'Bob': 30, 'Charlie': [1]

Drag options to blanks, or click blank then click option'

A35

B'35'

C[35]

D(35)

Attempts:

3 left

💡 Hint

Common Mistakes

Putting the number 35 in quotes, making it a string instead of an integer.

The value for 'Charlie' should be an integer representing age, so 35 without quotes is correct.

2fill in blank

medium

Complete the code to access the value for key 'name' in the dictionary.

Python

person = {'name': 'John', 'age': 22}
print(person[1])

Drag options to blanks, or click blank then click option'

A['age']

B['name']

C['john']

D['Name']

Attempts:

3 left

💡 Hint

Common Mistakes

Using a wrong key name or wrong case, which causes a KeyError.

To get the value for the key 'name', use person['name'].

3fill in blank

hard

Fix the error in the code to add a new key-value pair to the dictionary.

Python

data = {'x': 10, 'y': 20}
data[1] = 30

Drag options to blanks, or click blank then click option'

A['z']

Bappend('z')

Cadd('z')

D.z

Attempts:

3 left

💡 Hint

Common Mistakes

Trying to use list methods like append on a dictionary.

To add a new key 'z' with value 30, use data['z'] = 30.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps numbers to their squares for numbers greater than 2.

Python

squares = {x: x[1]2 for x in range(1, 6) if x [2] 2 }

Drag options to blanks, or click blank then click option'

A**

B+

C>

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+' instead of '**' for power, or using '<' instead of '>' for the condition.

The operator for power is '**' and the condition to filter numbers greater than 2 is '>'.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase keys to values only if the value is positive.

Python

result = [1]: [2] for k, v in data.items() if v [3] 0 }

Drag options to blanks, or click blank then click option'

Ak.upper()

Bv

C>

Dk.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using k.lower() instead of k.upper(), or using '<' instead of '>' for filtering.

Use k.upper() for uppercase keys, v for values, and '>' to filter positive values.

Practice

1. Why do programmers use dictionaries in Python?
my_dict = {'name': 'Alice', 'age': 25}

easy

A. To create loops automatically

B. To store data with unique keys for quick access

C. To perform mathematical calculations faster

D. To store data in a fixed order only

Solution

1. Step 1: Understand dictionary structure

   Dictionaries store data as key-value pairs, where each key is unique.

2. Step 2: Identify the main use

   This structure allows quick access to values using keys, unlike lists which use indexes.

3. Final Answer:

   To store data with unique keys for quick access -> Option B

4. Quick Check:

   Dictionaries = unique keys + fast access [OK]

Hint: Dictionaries use keys to find data fast [OK]

Common Mistakes:

• Thinking dictionaries store data in order only
• Confusing dictionaries with lists for calculations
• Believing dictionaries create loops automatically

2. Which of the following is the correct way to create a dictionary in Python?

easy

A. my_dict = ('key1', 'value1', 'key2', 'value2')

B. my_dict = ['key1', 'value1', 'key2', 'value2']

C. my_dict = {'key1': 'value1', 'key2': 'value2'}

D. my_dict = 'key1': 'value1', 'key2': 'value2'

Solution

1. Step 1: Recognize dictionary syntax

   Dictionaries use curly braces {} with key:value pairs separated by commas.

2. Step 2: Compare options

   my_dict = {'key1': 'value1', 'key2': 'value2'} uses correct syntax with braces and colons; others use lists, tuples, or invalid syntax.

3. Final Answer:

   my_dict = {'key1': 'value1', 'key2': 'value2'} -> Option C

4. Quick Check:

   Curly braces + key:value pairs = dictionary [OK]

Hint: Dictionaries use curly braces and colons [OK]

Common Mistakes:

• Using square brackets instead of curly braces
• Using tuples instead of dictionaries
• Missing curly braces or colons

3. What will be the output of this code?

phone_book = {'Alice': '1234', 'Bob': '5678'}
print(phone_book['Bob'])

medium

A. 5678

B. Bob

C. 1234

D. KeyError

Solution

1. Step 1: Understand dictionary key access

   Accessing phone_book['Bob'] retrieves the value for key 'Bob'.

2. Step 2: Find the value for 'Bob'

   In the dictionary, 'Bob' maps to '5678'.

3. Final Answer:

   5678 -> Option A

4. Quick Check:

   phone_book['Bob'] = '5678' [OK]

Hint: Access value by key inside brackets [OK]

Common Mistakes:

• Confusing keys and values
• Expecting the key name as output
• Mistyping key causing KeyError

4. Find the error in this code that tries to add a new entry to a dictionary:

contacts = {'John': '1111'}
contacts.add('Mary', '2222')

medium

A. Missing parentheses in dictionary creation

B. Dictionary keys cannot be names

C. Keys must be integers, not strings

D. Using .add() method which does not exist for dictionaries

Solution

1. Step 1: Check method used to add items

   Dictionaries do not have an .add() method; items are added by assignment.

2. Step 2: Correct way to add entry

   Use contacts['Mary'] = '2222' to add a new key-value pair.

3. Final Answer:

   Using .add() method which does not exist for dictionaries -> Option D

4. Quick Check:

   Add items by assignment, not .add() [OK]

Hint: Add dict items with assignment, not .add() [OK]

Common Mistakes:

• Trying to use set methods on dictionaries
• Confusing dictionary syntax with list methods
• Assuming keys must be numbers

5. You have a list of students and their scores:

students = [('Anna', 85), ('Ben', 90), ('Anna', 95)]

How can you create a dictionary that stores the highest score for each student?

hard

A. Use a loop to update the dictionary only if the new score is higher

B. Use a dictionary comprehension without conditions

C. Store all scores in a list as dictionary values

D. Use a set instead of a dictionary

Solution

1. Step 1: Understand the problem

   We want one highest score per student, so duplicates must be checked.

2. Step 2: Use a loop to update scores

   Loop through the list, and for each student, update the dictionary only if the new score is higher than the current stored score.

3. Final Answer:

   Use a loop to update the dictionary only if the new score is higher -> Option A

4. Quick Check:

   Update dict with max score per key [OK]

Hint: Update dict values only if new value is higher [OK]

Common Mistakes:

• Using comprehension without checking scores
• Storing multiple scores instead of highest
• Using sets which don't map keys to values