Union and intersection in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a union of two sets.

Python

set1 = {1, 2, 3}
set2 = {3, 4, 5}
result = set1 [1] set2
print(result)

Drag options to blanks, or click blank then click option'

A+

B&

C-

D|

Attempts:

3 left

💡 Hint

Common Mistakes

Using & instead of | results in intersection, not union.

Using + causes an error because sets don't support +.

The | operator creates a union of two sets, combining all unique elements.

2fill in blank

medium

Complete the code to find the intersection of two sets.

Python

a = {10, 20, 30}
b = {20, 40, 50}
common = a [1] b
print(common)

Drag options to blanks, or click blank then click option'

A&

B|

C-

D^

Attempts:

3 left

💡 Hint

Common Mistakes

Using | results in union, not intersection.

Using - gives difference, not intersection.

The & operator finds the intersection of two sets, elements common to both.

3fill in blank

hard

Fix the error in the code to get the union of two sets.

Python

set_a = {1, 2}
set_b = {2, 3}
union_set = set_a.[1](set_b)
print(union_set)

Drag options to blanks, or click blank then click option'

Aunion

Bintersect

Cadd

Dappend

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'intersect' which is not a valid set method.

Using 'add' or 'append' which are for adding single elements.

The correct method to get the union of two sets is union().

4fill in blank

hard

Fill both blanks to create a dictionary with word lengths for words longer than 3 letters.

Python

words = ['apple', 'bat', 'carrot', 'dog']
lengths = {word: [1] for word in words if len(word) [2] 3}
print(lengths)

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Alen(word)

Bword

C>

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using word instead of length for values.

Using <= instead of > in the condition.

The dictionary comprehension uses len(word) for values and filters words with length greater than 3 using >.

5fill in blank

hard

Fill all three blanks to create a dictionary of uppercase words with their lengths for words longer than 3 letters.

Python

words = ['apple', 'bat', 'carrot', 'dog']
result = [1]: [2] for w in words if len(w) [3] 3}
print(result)

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Aw.upper()

Blen(w)

C>

Dw.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using w.lower() instead of uppercase.

Using <= instead of > in the condition.

The dictionary comprehension uses w.upper() as keys, len(w) as values, and filters words longer than 3 with >.