type() and isinstance() in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check the type of variable x.

Python

x = 10
print(type(x) == [1])

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Afloat

Bstr

Clist

Dint

Attempts:

3 left

💡 Hint

Common Mistakes

Using quotes around the type name like 'int' instead of int.

Confusing int with str or float.

The type() function returns the type of the object. Since x is 10, which is an integer, type(x) equals int.

2fill in blank

medium

Complete the code to check if value is an instance of list.

Python

value = [1, 2, 3]
print(isinstance(value, [1]))

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Alist

Bdict

Cset

Dtuple

Attempts:

3 left

💡 Hint

Common Mistakes

Using type() instead of isinstance() for type checking.

Choosing the wrong type like tuple or dict.

The isinstance() function checks if the object is an instance of the given type. Here, value is a list, so isinstance(value, list) returns True.

3fill in blank

hard

Fix the error in the code to correctly check if data is a string.

Python

data = 'hello'
if isinstance(data, [1]):
    print('It is a string')

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Alist

Bint

Cstr

Dbool

Attempts:

3 left

💡 Hint

Common Mistakes

Using quotes around the type name like 'str'.

Checking against wrong types like int or list.

The isinstance() function needs the type str to check if data is a string. Using str here returns True.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps each word to its length only if the length is greater than 3.

Python

words = ['apple', 'bat', 'car', 'door']
lengths = {word: [1] for word in words if [2] > 3}

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Alen(word)

Bword

Attempts:

3 left

💡 Hint

Common Mistakes

Using word instead of len(word) for the value.

Comparing word directly to 3 instead of its length.

The dictionary comprehension maps each word to its length using len(word). The condition filters words with length greater than 3 using len(word) > 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their lengths only if the length is greater than 3.

Python

words = ['apple', 'bat', 'car', 'door']
result = { [1]: [2] for word in words if [3] > 3 }

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Aword.upper()

Blen(word)

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using word instead of word.upper() for keys.

Comparing word directly to 3 instead of its length.

The dictionary comprehension uses word.upper() as the key, len(word) as the value, and filters words with length greater than 3 using len(word) > 3.