Tuple methods in Python - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of count() method on a tuple

What is the output of this Python code?

t = (1, 2, 3, 2, 2, 4)
print(t.count(2))

Python

t = (1, 2, 3, 2, 2, 4)
print(t.count(2))

A 3

B 2

C 1

D 0

💡 Hint

The count() method returns how many times the given value appears in the tuple.

The number 2 appears three times in the tuple, so t.count(2) returns 3.

❓ Predict Output

intermediate

Output of index() method with repeated elements

What will this code print?

t = ('a', 'b', 'c', 'b', 'd')
print(t.index('b'))

Python

t = ('a', 'b', 'c', 'b', 'd')
print(t.index('b'))

A 2

B 3

C 4

D 1

💡 Hint

The index() method returns the first position of the value.

The first 'b' is at position 1 (counting from zero), so t.index('b') returns 1.

❓ Predict Output

advanced

What error does this code raise?

What error will this code produce?

t = (1, 2, 3)
print(t.index(4))

Python

t = (1, 2, 3)
print(t.index(4))

A ValueError

B IndexError

C TypeError

D KeyError

💡 Hint

The value 4 is not in the tuple, so index() cannot find it.

Calling index() with a value not in the tuple raises a ValueError.

❓ Predict Output

advanced

Output of count() with no matching elements

What does this code print?

t = ('x', 'y', 'z')
print(t.count('a'))

Python

t = ('x', 'y', 'z')
print(t.count('a'))

A 1

B None

C 0

D KeyError

💡 Hint

count() returns zero if the value is not found.

Since 'a' is not in the tuple, count() returns 0.

🧠 Conceptual

expert

Why can't you use append() on a tuple?

Which statement best explains why the tuple method append() does not exist?

A Tuples do not support any methods at all.

B Tuples are immutable, so their size and contents cannot be changed after creation.

C append() is only for strings, not tuples.

D append() is a method only for dictionaries.

💡 Hint

Think about whether tuples can be changed after you make them.

Tuples cannot be changed after creation, so methods that modify them like append() do not exist.

Practice

1. Which tuple method tells you how many times a specific value appears in the tuple?

easy

A. count()

B. index()

C. find()

D. length()

Solution

1. Step 1: Understand tuple methods

   The count() method returns how many times a value appears in a tuple.

2. Step 2: Compare with other methods

   index() finds the position, find() and length() are not tuple methods.

3. Final Answer:

   count() -> Option A

4. Quick Check:

   count() = count occurrences [OK]

Hint: count() counts occurrences of a value in tuple [OK]

Common Mistakes:

• Confusing count() with index()
• Using find() which is for strings
• Thinking length() works on tuples

2. Which of the following is the correct syntax to find the first index of value 5 in tuple t = (1, 5, 3, 5)?

easy

A. t.find(5)

B. t.count(5)

C. index(t, 5)

D. t.index(5)

Solution

1. Step 1: Recall tuple index method syntax

   The correct syntax is tuple_variable.index(value).

2. Step 2: Check options

   Only t.index(5) matches the correct syntax.

3. Final Answer:

   t.index(5) -> Option D

4. Quick Check:

   tuple.index(value) = correct syntax [OK]

Hint: Use tuple.index(value) to find first position [OK]

Common Mistakes:

• Using count() instead of index()
• Trying to call find() on tuple
• Calling index() as a standalone function

3. What is the output of this code?

t = (2, 4, 2, 6, 2)
print(t.count(2))
print(t.index(6))

medium

A. 2 and 4

B. 3 and 3

C. 3 and 4

D. Error

Solution

1. Step 1: Count occurrences of 2 in tuple

   Value 2 appears 3 times in t.

2. Step 2: Find index of 6 in tuple

   6 is at position 3 (0-based index).

3. Final Answer:

   3 and 4 -> Option C

4. Quick Check:

   count(2)=3, index(6)=3 [OK]

Hint: count() returns total, index() returns first position [OK]

Common Mistakes:

• Counting index as 4 instead of 3
• Mixing count and index results
• Expecting count to return index

4. What is wrong with this code?

t = (1, 2, 3)
print(t.index(4))

medium

A. Raises ValueError because 4 is not in tuple

B. No error, prints -1

C. SyntaxError due to wrong method

D. Returns None

Solution

1. Step 1: Check if 4 is in tuple

   Value 4 is not present in t.

2. Step 2: Understand index() behavior when value missing

   index() raises ValueError if value is not found.

3. Final Answer:

   Raises ValueError because 4 is not in tuple -> Option A

4. Quick Check:

   index() missing value = ValueError [OK]

Hint: index() errors if value not found, no -1 return [OK]

Common Mistakes:

• Expecting -1 when value not found
• Thinking index() returns None
• Confusing with list find() method

5. Given t = (1, 7, 3, 7, 5), which code finds the index of the second occurrence of 7?

hard

A. t.index(7, 1)

B. t.index(7, t.index(7) + 1)

C. t.count(7) - 1

D. t.index(7) + 1

Solution

1. Step 1: Find first index of 7

   t.index(7) returns 1, the first occurrence.

2. Step 2: Use start parameter to find second occurrence

   Calling t.index(7, 2) starts search after first 7, returning index 3.

3. Step 3: Combine steps in one expression

   t.index(7, t.index(7) + 1) finds second occurrence correctly.

4. Final Answer:

   t.index(7, t.index(7) + 1) -> Option B

5. Quick Check:

   Use index(value, start) for next occurrence [OK]

Hint: Use index(value, start) to find later occurrences [OK]

Common Mistakes:

• Using count() instead of index()
• Not adding 1 to start index
• Assuming index() returns all positions