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Recall & Review
beginner
What is tuple indexing in Python?
Tuple indexing means accessing individual elements of a tuple using their position number, starting from 0 for the first element.
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beginner
How do you access the last element of a tuple named t?
You use negative indexing: t[-1] gives the last element of the tuple.
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beginner
What does tuple slicing do?
Tuple slicing extracts a part of the tuple by specifying a start and end position, returning a new tuple with those elements.
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beginner
Explain the syntax of tuple slicing with an example.
Syntax: tuple[start:end] extracts elements from index start up to but not including end. For example, t = (10, 20, 30, 40); t[1:3] returns (20, 30).
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beginner
Can you change an element of a tuple using indexing?
No, tuples are immutable. You cannot change elements by indexing. You can only read elements.
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What will t[2] return if t = (5, 10, 15, 20)?
A20
B10
C15
D5
✗ Incorrect
t[2] accesses the element at index 2, which is the third element, 15.
What does t[-2] return for t = (1, 2, 3, 4, 5)?
A2
B3
C5
D4
✗ Incorrect
Negative index -2 means the second last element, which is 4.
What is the result of t[1:4] if t = (7, 8, 9, 10, 11)?
A(8, 9, 10)
B(7, 8, 9, 10)
C(9, 10, 11)
D(8, 9, 10, 11)
✗ Incorrect
Slicing from index 1 to 4 extracts elements at positions 1, 2, and 3: (8, 9, 10).
Which of these is NOT a valid way to slice a tuple t?
At[2:]
Bt(1:3)
Ct[1:5:2]
Dt[:3]
✗ Incorrect
Parentheses with colon like t(1:3) is invalid syntax. Use square brackets for slicing.
Can you assign a new value to t[0] if t = (1, 2, 3)?
ANo, tuples are immutable.
BYes, tuples are mutable.
COnly if you use slicing.
DOnly if you convert to a list first.
✗ Incorrect
Tuples cannot be changed after creation; they are immutable.
Describe how to access elements in a tuple using indexing and negative indexing.
Think about counting positions from the start and from the end.
You got /3 concepts.
Explain how tuple slicing works and what the result looks like.
Imagine cutting a piece from a string or a list.
You got /4 concepts.
Practice
(1/5)
1.
What does my_tuple[2] return if my_tuple = (10, 20, 30, 40)?
easy
A. 30
B. 20
C. 40
D. 10
Solution
Step 1: Understand tuple indexing
Indexing starts at 0, so index 2 means the third item in the tuple.
Step 2: Identify the item at index 2
The tuple is (10, 20, 30, 40), so the item at index 2 is 30.
Final Answer:
30 -> Option A
Quick Check:
Index 2 in tuple = 30 [OK]
Hint: Remember: indexing starts at zero in tuples [OK]
Common Mistakes:
Counting from 1 instead of 0
Confusing index 2 with index 3
Mixing up tuple with list indexing
2.
Which of the following is the correct syntax to get the last item of a tuple t?
easy
A. t[1]
B. t[-1]
C. t[last]
D. t[len(t)]
Solution
Step 1: Recall negative indexing in tuples
Negative index -1 accesses the last item in a tuple.
Step 2: Check each option
t[-1] correctly accesses the last item. t[1] accesses second item, t[last] is invalid syntax, t[len(t)] causes IndexError because indexing starts at 0.
Final Answer:
t[-1] -> Option B
Quick Check:
Last item index = -1 [OK]
Hint: Use -1 to get last item from any tuple [OK]
Common Mistakes:
Using len(t) as index (out of range)
Trying to use variable 'last' as index
Confusing positive and negative indexes
3.
What is the output of this code?
t = (5, 10, 15, 20, 25)
print(t[1:4])
medium
A. (10, 15, 20)
B. (10, 15, 20, 25)
C. (5, 10, 15)
D. (15, 20, 25)
Solution
Step 1: Understand slicing syntax
Slicing t[1:4] means start at index 1 up to but not including index 4.
Step 2: Extract the slice from the tuple
Tuple is (5, 10, 15, 20, 25). Index 1 is 10, index 2 is 15, index 3 is 20. Index 4 (25) is excluded.
Final Answer:
(10, 15, 20) -> Option A
Quick Check:
Slicing excludes end index [OK]
Hint: Slice excludes the end index, so stop before it [OK]
Common Mistakes:
Including the end index in slice
Confusing indexes with values
Using parentheses instead of brackets for slicing
4.
Find the error in this code:
t = (1, 2, 3, 4, 5)
print(t[5])
medium
A. Prints 5
B. SyntaxError
C. IndexError: tuple index out of range
D. Prints 1
Solution
Step 1: Check tuple length and indexing
Tuple has 5 items indexed 0 to 4. Index 5 is outside this range.
Step 2: Understand what happens when accessing invalid index
Accessing t[5] causes an IndexError because the index is out of range.
Final Answer:
IndexError: tuple index out of range -> Option C
Quick Check:
Index must be less than length [OK]
Hint: Index must be less than tuple length [OK]
Common Mistakes:
Using index equal to length
Confusing SyntaxError with IndexError
Assuming last index is length instead of length-1
5.
Given t = (2, 4, 6, 8, 10, 12), which expression returns a tuple with every second item starting from the last item going backwards?
hard
A. t[1::2]
B. t[::2]
C. t[-2::-1]
D. t[::-2]
Solution
Step 1: Understand slicing with negative step
A negative step means slicing backwards. t[::-2] starts from the end and takes every second item backwards.
Step 2: Check what t[::-2] returns
Tuple is (2,4,6,8,10,12). t[::-2] picks 12 (last), 8, 4, resulting in (12, 8, 4).