String validation checks in Python - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of string isalnum() method

What is the output of this Python code snippet?

Python

s = "Hello123"
print(s.isalnum())

A True

B False

C SyntaxError

D TypeError

💡 Hint

isalnum() returns True if all characters are letters or digits and string is not empty.

The string "Hello123" contains only letters and digits, so isalnum() returns True.

❓ Predict Output

intermediate

Output of string isdigit() with spaces

What will this code print?

Python

s = "123 456"
print(s.isdigit())

A False

B True

C SyntaxError

D TypeError

💡 Hint

Spaces are not digits.

The string contains a space character, which is not a digit, so isdigit() returns False.

❓ Predict Output

advanced

Result of islower() on mixed case string

What does this code output?

Python

s = "helloWorld"
print(s.islower())

A True

B SyntaxError

C TypeError

D False

💡 Hint

islower() returns True only if all letters are lowercase and there is at least one letter.

The string "helloWorld" has uppercase 'W', so islower() returns False.

❓ Predict Output

advanced

Output of isspace() with newline character

What will this code print?

Python

s = "\n"
print(s.isspace())

A False

B True

C SyntaxError

D TypeError

💡 Hint

isspace() returns True if all characters are whitespace characters.

The newline character is considered whitespace, so isspace() returns True.

❓ Predict Output

expert

Output of complex string validation expression

What is the output of this code?

Python

s = "Python3"
result = s.isalpha() or s.isalnum() and not s.isdigit()
print(result)

A False

B SyntaxError

C True

D TypeError

💡 Hint

Remember operator precedence: 'and' before 'or'.

Expression evaluates as s.isalpha() or (s.isalnum() and not s.isdigit()). s.isalpha() is False because of '3'. s.isalnum() is True, s.isdigit() is False, so overall True.

Practice

1. Which Python string method checks if all characters in a string are letters (a-z or A-Z)?

easy

A. isdigit()

B. isalpha()

C. isalnum()

D. isspace()

Solution

1. Step 1: Understand what isalpha() does

   The isalpha() method returns True if all characters in the string are alphabet letters only.

2. Step 2: Compare with other methods

   isdigit() checks for digits only, isalnum() checks for letters or digits, and isspace() checks for whitespace characters.

3. Final Answer:

   isalpha() -> Option B

4. Quick Check:

   Check letters only = isalpha() [OK]

Hint: Letters only? Use isalpha() method [OK]

Common Mistakes:

• Confusing isalpha() with isdigit()
• Using isalnum() which allows digits too
• Thinking isspace() checks letters

2. Which of the following is the correct syntax to check if a string s contains only digits in Python?

easy

A. if s.isdigit()

B. if s.isdigit:

C. if isdigit(s)

D. if s.is_digit()

Solution

1. Step 1: Recall method call syntax in Python

   Methods require parentheses to call them, so s.isdigit() is correct.

2. Step 2: Identify incorrect options

   s.isdigit misses parentheses, isdigit(s) is not a built-in function, and s.is_digit() is not a valid method.

3. Final Answer:

   if s.isdigit() -> Option A

4. Quick Check:

   Method call needs () = isdigit() [OK]

Hint: Call string methods with parentheses () [OK]

Common Mistakes:

• Forgetting parentheses after method name
• Using wrong method names like is_digit()
• Trying to call isdigit as a function

3. What will be the output of this code?

text = "Hello123"
print(text.isalnum())
print(text.isalpha())

medium

A. True\nTrue

B. False\nFalse

C. True\nFalse

D. False\nTrue

Solution

1. Step 1: Check text.isalnum()

   The string "Hello123" contains letters and digits only, so isalnum() returns True.

2. Step 2: Check text.isalpha()

   Since the string contains digits, isalpha() returns False.

3. Final Answer:

   True\nFalse -> Option C

4. Quick Check:

   Letters+digits = True, letters only = False [OK]

Hint: isalnum() allows digits; isalpha() does not [OK]

Common Mistakes:

• Assuming isalpha() returns True with digits
• Confusing isalnum() with isalpha()
• Ignoring that digits affect isalpha()

4. Find the error in this code snippet:

user_input = " 123 "
if user_input.isdigit():
    print("Digits only")
else:
    print("Not digits only")

medium

A. The string has spaces, so isdigit() returns False

B. The method isdigit() is misspelled

C. The print statement is missing parentheses

D. The variable user_input is not defined

Solution

1. Step 1: Understand what isdigit() checks

   isdigit() returns True only if all characters are digits without spaces or other characters.

2. Step 2: Analyze the string " 123 "

   The string contains spaces, so isdigit() returns False, causing the else branch to run.

3. Final Answer:

   The string has spaces, so isdigit() returns False -> Option A

4. Quick Check:

   Spaces cause isdigit() to fail [OK]

Hint: Spaces cause isdigit() to return False [OK]

Common Mistakes:

• Ignoring spaces in the string
• Thinking isdigit() ignores whitespace
• Assuming method name is wrong

5. You want to check if a string s contains only printable characters and no spaces. Which combination of methods correctly validates this?

hard

A. s.isprintable() and s.isalnum()

B. s.isprintable() and not s.isspace()

C. s.isprintable() and not s.isalpha()

D. s.isprintable() and not ' ' in s

Solution

1. Step 1: Understand isprintable()

   This method returns True if all characters are printable (letters, digits, punctuation, etc.) including spaces.

2. Step 2: Exclude spaces explicitly

   Since spaces are printable, to ensure no spaces, check that the space character ' ' is not in the string.

3. Step 3: Evaluate options

   s.isprintable() and not ' ' in s uses not ' ' in s to exclude spaces, combined with isprintable(), which is correct. s.isprintable() and not s.isspace() fails because not s.isspace() only checks if the whole string is not spaces, but allows spaces mixed with other chars. Options C and D do not correctly exclude spaces.

4. Final Answer:

   s.isprintable() and not ' ' in s -> Option D

5. Quick Check:

   Exclude spaces by checking ' ' not in string [OK]

Hint: Check printable and exclude spaces with ' ' not in s [OK]

Common Mistakes:

• Using isspace() to exclude spaces incorrectly
• Assuming isprintable() excludes spaces
• Using isalnum() which excludes punctuation