sorted() function in Python - Step-by-Step Execution

Concept Flow - sorted() function

Start with iterable

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Call sorted()

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Compare elements

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Arrange elements in order

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Return new sorted list

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End

The sorted() function takes an iterable, compares its elements, arranges them in order, and returns a new sorted list.

Execution Sample

Python

numbers = [3, 1, 4, 1]
sorted_numbers = sorted(numbers)
print(sorted_numbers)

This code sorts the list 'numbers' and prints the sorted list.

Execution Table

Step	Action	Iterable State	Comparison	Result
1	Start with numbers = [3, 1, 4, 1]	[3, 1, 4, 1]	N/A	N/A
2	Call sorted(numbers)	[3, 1, 4, 1]	Compare 3 and 1	1 < 3, so 1 comes first
3	Compare 3 and 4	[3, 1, 4, 1]	3 < 4	3 comes before 4
4	Compare 1 and 3	[3, 1, 4, 1]	1 < 3	1 comes before 3
5	Arrange elements	[3, 1, 4, 1]	N/A	[1, 1, 3, 4]
6	Return new sorted list	[3, 1, 4, 1]	N/A	[1, 1, 3, 4]
7	Print sorted_numbers	[3, 1, 4, 1]	N/A	Output: [1, 1, 3, 4]

💡 All elements compared and arranged; sorted() returns new sorted list.

Variable Tracker

Variable	Start	After sorted()	Final
numbers	[3, 1, 4, 1]	[3, 1, 4, 1]	[3, 1, 4, 1]
sorted_numbers	N/A	[1, 1, 3, 4]	[1, 1, 3, 4]

Key Moments - 3 Insights

Does sorted() change the original list?

No, sorted() returns a new sorted list and does not modify the original list 'numbers' as shown in variable_tracker rows 1 and 2.

What type of object does sorted() return?

sorted() always returns a new list, even if the input is another iterable type, as shown in execution_table step 6.

Why do we see multiple comparisons in the execution_table?

sorted() compares elements pairwise to decide their order, which is why steps 2 to 4 show comparisons before arranging the final list.

Visual Quiz - 3 Questions

Look at the execution_table at step 5, what is the arranged list?

A [4, 3, 1, 1]

B [1, 1, 3, 4]

C [3, 1, 4, 1]

D [1, 3, 1, 4]

💡 Hint

Check the 'Result' column at step 5 in the execution_table.

According to variable_tracker, what is the value of 'numbers' after sorted() is called?

A [3, 1, 4, 1]

B [1, 1, 3, 4]

C N/A

D []

💡 Hint

Look at the 'numbers' row in variable_tracker after sorted() call.

If we change 'numbers' to a tuple, what will sorted() return?

A A sorted tuple

B An error

C A sorted list

D The original tuple unchanged

💡 Hint

Recall that sorted() always returns a list regardless of input type.

Concept Snapshot

sorted(iterable) returns a new list with elements sorted in ascending order.
It does not change the original iterable.
Works with any iterable (list, tuple, string).
You can provide key and reverse parameters for custom sorting.
Always returns a list.

Full Transcript

The sorted() function takes an iterable like a list and returns a new list with the elements arranged in ascending order. It compares elements pairwise to decide their order. The original list remains unchanged. The returned object is always a list, even if the input is a tuple or string. This example shows sorting a list of numbers and printing the sorted result.