Searching and counting elements in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to count how many times the number 5 appears in the list.

Python

numbers = [1, 5, 3, 5, 7, 5]
count_fives = numbers.[1](5)
print(count_fives)

Drag options to blanks, or click blank then click option'

Aindex

Bcount

Cfind

Dsearch

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'index' instead of 'count' which only finds the first position.

The count method counts how many times a value appears in a list.

2fill in blank

medium

Complete the code to check if the word 'apple' is in the list of fruits.

Python

fruits = ['banana', 'orange', 'apple', 'grape']
if 'apple' [1] fruits:
    print('Found apple!')

Drag options to blanks, or click blank then click option'

Ain

Bhas

Cnot

Dis

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'is' which checks identity, not membership.

The keyword in checks if an item exists in a list.

3fill in blank

hard

Fix the error in the code to find the index of the first occurrence of 7 in the list.

Python

values = [4, 7, 2, 7, 9]
position = values.[1](7)
print(position)

Drag options to blanks, or click blank then click option'

Alocate

Bfind

Csearch

Dindex

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'find' which is not a list method and causes an error.

The index method returns the position of the first matching element in a list.

4fill in blank

hard

Fill both blanks to create a dictionary with words as keys and their lengths as values, but only for words longer than 4 letters.

Python

word_lengths = {word: [1] for word in words if len(word) [2] 4}

Drag options to blanks, or click blank then click option'

Alen(word)

B<=

C>

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<=' instead of '>' which selects shorter words.

Use len(word) to get the length, and > to filter words longer than 4 letters.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase words as keys and their counts as values, but only for words that appear more than once.

Python

word_counts = { [1] : words.count([2]) for [3] in words if words.count([3]) > 1 }

Drag options to blanks, or click blank then click option'

Aword.upper()

Bword

Ditem

Attempts:

3 left

💡 Hint

Common Mistakes

Using different variable names inconsistently.

Use word.upper() for keys, count the word itself, and iterate with word.