Local scope in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define a local variable x inside the function.

Python

def my_function():
    [1] = 10
    print(x)

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Ax

Bz

Cy

Dvalue

Attempts:

3 left

💡 Hint

Common Mistakes

Using a different variable name than the one printed.

Defining the variable outside the function.

The variable x is defined locally inside the function. This means it only exists inside my_function.

2fill in blank

medium

Complete the code to return the local variable result from the function.

Python

def calculate():
    result = 5 + 3
    return [1]

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Avalue

Bresult

Ctotal

Dx

Attempts:

3 left

💡 Hint

Common Mistakes

Returning a variable not defined inside the function.

Returning a variable with a different name.

The function returns the local variable result which holds the sum.

3fill in blank

hard

Fix the error by completing the code to access the local variable count inside the function.

Python

def counter():
    count = 0
    count += 1
    print([1])

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Avalue

Bcounter

Ctotal

Dcount

Attempts:

3 left

💡 Hint

Common Mistakes

Trying to print a variable not defined inside the function.

Using the function name instead of the variable.

The variable count is local and must be used inside the function to print its value.

4fill in blank

hard

Fill both blanks to create a dictionary with keys as words and values as their lengths, only for words longer than 3 letters.

Python

words = ['apple', 'cat', 'banana', 'dog']
lengths = {word: [1] for word in words if len(word) [2] 3}

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Alen(word)

B>

C<

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as the value instead of its length.

Using the wrong comparison operator.

The dictionary comprehension uses len(word) for values and filters words with length greater than 3.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys and values only if the value is greater than 0.

Python

data = {'a': 1, 'b': 0, 'c': 3}
result = { [1]: [2] for k, v in data.items() if v [3] 0 }

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Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Not converting keys to uppercase.

Including values that are zero or less.

Swapping keys and values.

The dictionary comprehension uses uppercase keys, original values, and filters values greater than zero.