Jump into concepts and practice - no test required
or
Recommended
Test this pattern10 questions across easy, medium, and hard to know if this pattern is strong
List comprehension with condition
๐ Scenario: You are working in a fruit store. You have a list of fruit names, but you only want to select the fruits that have more than 5 letters in their names.
๐ฏ Goal: Build a Python program that uses list comprehension with a condition to create a new list containing only the fruits with names longer than 5 letters.
๐ What You'll Learn
Create a list called fruits with the exact values: 'apple', 'banana', 'kiwi', 'mango', 'pineapple', 'pear'
Create a variable called min_length and set it to 5
Use a list comprehension with a condition to create a new list called long_fruits that contains only fruits with length greater than min_length
Print the long_fruits list
๐ก Why This Matters
๐ Real World
Filtering lists based on conditions is common in data processing, like selecting products, names, or records that meet certain criteria.
๐ผ Career
Understanding list comprehension with conditions helps in writing clean and efficient code for data analysis, web development, and automation tasks.
Progress0 / 4 steps
1
Create the initial list of fruits
Create a list called fruits with these exact values: 'apple', 'banana', 'kiwi', 'mango', 'pineapple', 'pear'
Python
Hint
Use square brackets [] to create a list and separate items with commas.
2
Set the minimum length for fruit names
Create a variable called min_length and set it to the number 5
Python
Hint
Use the equals sign = to assign the value 5 to the variable min_length.
3
Use list comprehension with condition
Use a list comprehension with a condition to create a new list called long_fruits that contains only fruits from fruits whose length is greater than min_length
Python
Hint
Use the syntax: [item for item in list if condition] to filter items.
4
Print the filtered list
Write a print statement to display the long_fruits list
Python
Hint
Use print(long_fruits) to show the result.
Practice
(1/5)
1. What does the following list comprehension do? [x for x in range(5) if x % 2 == 0]
easy
A. Creates a list of odd numbers from 0 to 4
B. Creates a list of even numbers from 0 to 4
C. Creates a list of numbers from 1 to 5
D. Creates a list of numbers divisible by 3
Solution
Step 1: Understand the range and condition
The range(5) generates numbers 0, 1, 2, 3, 4. The condition x % 2 == 0 selects numbers divisible by 2 (even numbers).
Step 2: Apply the condition to each number
From 0 to 4, the even numbers are 0, 2, and 4. These are included in the new list.
Final Answer:
[0, 2, 4] -> Option B
Quick Check:
Even numbers from 0 to 4 = [0, 2, 4] [OK]
Hint: Look for the condition after 'if' to filter items [OK]
Common Mistakes:
Confusing even and odd numbers
Ignoring the condition and taking all numbers
Misunderstanding the range function
2. Which of the following is the correct syntax for a list comprehension that selects numbers greater than 10 from list nums?
easy
A. [x for x > 10 in nums]
B. [x if x > 10 for x in nums]
C. [if x > 10 for x in nums]
D. [x for x in nums if x > 10]
Solution
Step 1: Recall list comprehension syntax
The correct syntax is [expression for item in iterable if condition]. Here, expression and item are both x, iterable is nums, and condition is x > 10.
Step 2: Check each option
[x for x in nums if x > 10] matches the correct syntax. The other options have misplaced or missing parts.
Final Answer:
[x for x in nums if x > 10] -> Option D
Quick Check:
Correct list comprehension syntax = [x for x in nums if x > 10] [OK]
Hint: Remember: for comes before if in list comprehension [OK]
Common Mistakes:
Placing 'if' before 'for'
Omitting 'for' keyword
Using incorrect order of clauses
3. What is the output of this code?
nums = [3, 7, 12, 5, 20]
result = [n*2 for n in nums if n > 6]
print(result)
medium
A. [14, 24, 40]
B. [3, 7, 12, 5, 20]
C. [6, 14, 24, 10, 40]
D. [12, 24, 40]
Solution
Step 1: Identify numbers greater than 6
From the list, numbers greater than 6 are 7, 12, and 20.
Step 2: Multiply each selected number by 2
7*2=14, 12*2=24, 20*2=40. These form the new list.
Final Answer:
[14, 24, 40] -> Option A
Quick Check:
Filter >6 and double = [14, 24, 40] [OK]
Hint: Apply condition first, then transform each item [OK]
Common Mistakes:
Multiplying all numbers, ignoring condition
Including numbers less than or equal to 6
Confusing multiplication with addition
4. Find the error in this list comprehension:
values = [1, 2, 3, 4]
new_values = [x for x in values if x > 2 else 0]
medium
A. SyntaxError due to incorrect use of else in list comprehension
B. No error, code runs fine
C. TypeError because of wrong condition
D. NameError because x is undefined
Solution
Step 1: Understand list comprehension with condition
In list comprehension, 'if' can be used to filter items, but 'else' must be part of a conditional expression, not after 'if' alone.
Step 2: Identify the syntax error
The code uses 'if x > 2 else 0' incorrectly. The correct way is to use a conditional expression inside the expression part, like [x if x > 2 else 0 for x in values].
Final Answer:
SyntaxError due to incorrect use of else in list comprehension -> Option A
Quick Check:
Else must be inside expression, not after if clause [OK]
Hint: Use if-else inside expression, not after if clause [OK]
Common Mistakes:
Placing else after if in list comprehension filter
Confusing filter condition with conditional expression
Ignoring Python syntax rules for comprehensions
5. You have a list of strings: words = ['apple', '', 'banana', 'cherry', '', 'date']. Which list comprehension creates a new list with only non-empty strings in uppercase?
hard
A. [w for w in words if w.upper()]
B. [w.upper() if w else w for w in words]
C. [w.upper() for w in words if w]
D. [w.upper() for w in words if w == '']
Solution
Step 1: Understand filtering non-empty strings
In Python, empty strings are false in boolean context. Using if w filters out empty strings.
Step 2: Convert filtered strings to uppercase
For each non-empty string w, w.upper() converts it to uppercase.
Final Answer:
[w.upper() for w in words if w] -> Option C
Quick Check:
Filter non-empty and uppercase = [w.upper() for w in words if w] [OK]
Hint: Use 'if w' to filter non-empty strings in list comprehension [OK]