Lambda with sorted() in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to sort the list of numbers in ascending order using sorted() with a lambda that returns the number itself.

Python

numbers = [5, 2, 9, 1]
sorted_numbers = sorted(numbers, key=lambda x: [1])
print(sorted_numbers)

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Alen(x)

Bx

Cx*2

Dx+1

Attempts:

3 left

💡 Hint

Common Mistakes

Using len(x) causes an error because numbers are integers, not sequences.

Using x*2 or x+1 changes the sorting order incorrectly.

The lambda function should return the number itself (x) to sort the list in ascending order.

2fill in blank

medium

Complete the code to sort the list of words by their length using sorted() and a lambda.

Python

words = ['apple', 'fig', 'banana', 'kiwi']
sorted_words = sorted(words, key=lambda w: [1])
print(sorted_words)

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Aw[0]

Bw.upper()

Clen(w)

Dw[::-1]

Attempts:

3 left

💡 Hint

Common Mistakes

Using w[0] sorts by first letter, not length.

Using w.upper() sorts alphabetically ignoring case.

Using w[::-1] sorts by reversed word, not length.

The lambda should return the length of each word (len(w)) to sort by word length.

3fill in blank

hard

Fix the error in the code to sort a list of tuples by the second element using sorted() and a lambda.

Python

pairs = [(1, 3), (2, 1), (3, 2)]
sorted_pairs = sorted(pairs, key=lambda x: [1])
print(sorted_pairs)

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Ax[1]

Bx[0]

Cx[2]

Dx

Attempts:

3 left

💡 Hint

Common Mistakes

Using x[0] sorts by the first element, not the second.

Using x[2] causes an IndexError because tuples have only two elements.

Using x sorts by the whole tuple, which sorts by first element then second.

To sort by the second element of each tuple, the lambda should return x[1].

4fill in blank

hard

Fill both blanks to create a dictionary of words and their lengths, but only include words longer than 3 characters.

Python

words = ['cat', 'elephant', 'dog', 'lion']
lengths = {word: [1] for word in words if [2]
print(lengths)

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Alen(word)

Bword > 3

Clen(word) > 3

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using word > 3 compares a string to a number, causing an error.

Using word alone in the condition includes all words.

Using len(word) without a comparison includes all words.

The dictionary values are the length of each word (len(word)), and the condition filters words longer than 3 characters (len(word) > 3).

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase words as keys and their lengths as values, including only words with length greater than 4.

Python

words = ['tree', 'mountain', 'river', 'sky']
result = [1]: [2] for w in words if [3]
print(result)

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Aw.upper()

Blen(w)

Clen(w) > 4

Dw.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using w.lower() for keys instead of uppercase.

Not filtering words by length.

Using w instead of w.upper() for keys.

Keys are uppercase words (w.upper()), values are lengths (len(w)), and only words longer than 4 are included (len(w) > 4).