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Test this pattern10 questions across easy, medium, and hard to know if this pattern is strong
Recall & Review
beginner
What is a lambda function in Python?
A lambda function is a small anonymous function defined with the lambda keyword. It can take any number of arguments but has only one expression, which is returned.
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beginner
What does the map() function do in Python?
map() applies a given function to each item of an iterable (like a list) and returns a map object with the results.
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beginner
How do you combine lambda and map() to square each number in a list?
You can write: list(map(lambda x: x**2, [1, 2, 3])) which returns [1, 4, 9].
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intermediate
Why use lambda with map() instead of a regular function?
Using lambda with map() lets you write quick, simple functions inline without defining a separate function with def.
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beginner
What type of object does map() return and how do you get a list from it?
map() returns a map object, which is an iterator. To get a list, wrap it with list(), like list(map(...)).
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What does this code return? list(map(lambda x: x + 1, [1, 2, 3]))
A[1, 3, 5]
B[1, 2, 3]
C[0, 1, 2]
D[2, 3, 4]
✗ Incorrect
The lambda adds 1 to each element, so 1+1=2, 2+1=3, 3+1=4.
Which of these is a correct way to use map() with a lambda to double numbers?
Amap(x => x * 2, [1, 2, 3])
Bmap(lambda x: x * 2, [1, 2, 3])
Cmap(lambda x: x + 2, [1, 2, 3])
Dmap(double, [1, 2, 3])
✗ Incorrect
Option B uses Python lambda syntax correctly to double each number.
What is the output type of map() before converting it?
Alist
Bdictionary
Cmap object (iterator)
Dstring
✗ Incorrect
map() returns a map object, which is an iterator.
Why might you prefer lambda with map() over a for-loop?
AIt allows concise, readable code for simple operations
BIt uses less memory
CIt is always faster
DIt can only be used with lists
✗ Incorrect
Using lambda with map() makes code shorter and clearer for simple tasks.
What will this code output? list(map(lambda x: x % 2 == 0, [1, 2, 3, 4]))
A[False, True, False, True]
B[1, 2, 3, 4]
C[True, False, True, False]
D[0, 1, 0, 1]
✗ Incorrect
The lambda checks if each number is even, returning True or False accordingly.
Explain how lambda functions work with map() in Python.
Think about how you can quickly change each item in a list without writing a full function.
You got /4 concepts.
Describe a real-life example where using lambda with map() would be helpful.
Imagine you want to quickly add tax to a list of prices.
You got /4 concepts.
Practice
(1/5)
1.
What does the map() function do when used with a lambda in Python?
easy
A. Creates a new list without changing items
B. Filters items based on a condition
C. Applies the lambda function to each item in the list
D. Sorts the list items
Solution
Step 1: Understand the role of map()
map() takes a function and a list, then applies the function to each item.
Step 2: Role of lambda with map()
The lambda defines a quick function to apply to each item in the list.
Final Answer:
Applies the lambda function to each item in the list -> Option C
Quick Check:
map() + lambda = apply function to each item [OK]
Hint: Remember: map applies function to every list item [OK]
Common Mistakes:
Thinking map filters items
Assuming map sorts the list
Believing map returns the original list unchanged
2.
Which of the following is the correct syntax to double each number in the list [1, 2, 3] using map() and lambda?
?
easy
A. map(lambda x: x * 2, [1, 2, 3])
B. list(map(lambda x: x * 2, [1, 2, 3]))
C. list(lambda x: x * 2, [1, 2, 3])
D. map([1, 2, 3], lambda x: x * 2)
Solution
Step 1: Check map() syntax
map() takes a function first, then the iterable (list).
Step 2: Convert map object to list
To see results, wrap map() with list().
Final Answer:
list(map(lambda x: x * 2, [1, 2, 3])) -> Option B
Quick Check:
Correct syntax = list(map(lambda x: x * 2, list)) [OK]
Hint: Use list() around map() to see results [OK]
Common Mistakes:
Forgetting to convert map to list
Swapping arguments in map()
Using lambda outside map() incorrectly
3.
What is the output of the following code?
nums = [1, 2, 3, 4]
result = list(map(lambda x: x + 1, nums))
print(result)
medium
A. [2, 3, 4, 5]
B. [1, 2, 3, 4]
C. [0, 1, 2, 3]
D. Error
Solution
Step 1: Understand the lambda function
The lambda adds 1 to each number in the list.
Step 2: Apply lambda to each item in nums
Each number 1,2,3,4 becomes 2,3,4,5 respectively.
Final Answer:
[2, 3, 4, 5] -> Option A
Quick Check:
Each item +1 = [2,3,4,5] [OK]
Hint: Add 1 to each item with lambda x: x + 1 [OK]
Common Mistakes:
Forgetting to convert map to list before print
Confusing addition with multiplication
Expecting original list unchanged
4.
Find the error in this code snippet:
numbers = [1, 2, 3]
result = map(lambda x: x ** 2, numbers)
print(result)
medium
A. map() requires two arguments but only one given
B. Lambda syntax is incorrect
C. List 'numbers' is not defined
D. Missing list() to convert map object before printing
Solution
Step 1: Check map() usage
map() returns a map object, not a list.
Step 2: Printing map object directly
Printing map object shows memory address, not values; convert to list first.
Final Answer:
Missing list() to convert map object before printing -> Option D
Quick Check:
Use list() to see map results [OK]
Hint: Wrap map() with list() before printing [OK]
Common Mistakes:
Trying to print map object directly
Thinking lambda syntax is wrong
Assuming map needs more arguments
5.
You have a list of strings representing numbers: ['1', '2', '3', '4']. Using map() and lambda, how do you convert this list to integers and then add 10 to each number?
hard
A. list(map(lambda x: int(x) + 10, ['1', '2', '3', '4']))
B. list(map(lambda x: x + 10, ['1', '2', '3', '4']))
C. list(map(int(x) + 10, ['1', '2', '3', '4']))
D. list(map(lambda x: int(x + 10), ['1', '2', '3', '4']))