Bird
Raised Fist0
Pythonprogramming~20 mins

Frozen set behavior in Python - Practice Problems & Coding Challenges

Choose your learning style10 modes available

Start learning this pattern below

Jump into concepts and practice - no test required

or
Recommended
Test this pattern10 questions across easy, medium, and hard to know if this pattern is strong
Challenge - 5 Problems
๐ŸŽ–๏ธ
Frozen Set Mastery
Get all challenges correct to earn this badge!
Test your skills under time pressure!
โ“ Predict Output
intermediate
2:00remaining
Output of frozen set union operation
What is the output of this Python code?
Python
a = frozenset([1, 2, 3])
b = frozenset([3, 4, 5])
result = a.union(b)
print(result)
Afrozenset({1, 2, 3, 4, 5})
B{1, 2, 3, 4, 5}
Cfrozenset([1, 2, 3, 4, 5])
DTypeError
Attempts:
2 left
๐Ÿ’ก Hint
Remember that union returns a set or frozen set depending on the caller.
โ“ Predict Output
intermediate
2:00remaining
Frozen set mutability test
What happens when you try to add an element to a frozen set?
Python
fs = frozenset([1, 2, 3])
fs.add(4)
Afrozenset({1, 2, 3, 4})
BTypeError
CAttributeError
DNo output, element added silently
Attempts:
2 left
๐Ÿ’ก Hint
Frozen sets do not support methods that modify them.
โ“ Predict Output
advanced
2:00remaining
Frozen set as dictionary key behavior
What is the output of this code?
Python
fs1 = frozenset([1, 2])
fs2 = frozenset([2, 1])
d = {fs1: 'value1'}
print(d[fs2])
ANone
BKeyError
CTypeError
Dvalue1
Attempts:
2 left
๐Ÿ’ก Hint
Frozen sets with the same elements are equal and hash the same.
โ“ Predict Output
advanced
2:00remaining
Frozen set intersection with mutable set
What is the output of this code?
Python
fs = frozenset([1, 2, 3])
s = {2, 3, 4}
result = fs.intersection(s)
print(result)
Afrozenset({2, 3})
B{2, 3}
CTypeError
Dfrozenset({4})
Attempts:
2 left
๐Ÿ’ก Hint
The intersection method returns the same type as the caller.
๐Ÿง  Conceptual
expert
2:00remaining
Why are frozen sets hashable but sets are not?
Which statement best explains why frozen sets can be used as dictionary keys but sets cannot?
ASets are mutable but frozen sets are implemented in C, making them hashable.
BFrozen sets are immutable, so their hash value does not change, while sets are mutable and unhashable.
CFrozen sets store elements in sorted order, sets do not.
DFrozen sets use less memory than sets, making them hashable.
Attempts:
2 left
๐Ÿ’ก Hint
Think about what makes an object usable as a dictionary key.

Practice

(1/5)
1. What is a key characteristic of a frozenset in Python?
easy
A. It is a type of list.
B. It allows duplicate elements.
C. It can be modified by adding or removing elements.
D. It is immutable and cannot be changed after creation.

Solution

  1. Step 1: Understand what a frozenset is

    A frozenset is a set that cannot be changed after it is created, meaning it is immutable.
  2. Step 2: Compare options with frozenset properties

    'It is immutable and cannot be changed after creation.' correctly states immutability. Claims that it allows duplicate elements or can be modified are false because frozensets do not allow duplicates and cannot be modified. 'It is a type of list.' is incorrect because frozensets are not lists.
  3. Final Answer:

    It is immutable and cannot be changed after creation. -> Option D
  4. Quick Check:

    Frozen set = immutable set [OK]
Hint: Remember: frozenset means frozen, so no changes allowed [OK]
Common Mistakes:
  • Thinking frozensets can be changed like normal sets
  • Confusing frozenset with list or tuple
  • Assuming duplicates are allowed
2. Which of the following is the correct way to create a frozenset from a list [1, 2, 3]?
easy
A. fs = frozenset([1, 2, 3])
B. fs = frozen_set([1, 2, 3])
C. fs = frozenset{1, 2, 3}
D. fs = frozenset(1, 2, 3)

Solution

  1. Step 1: Recall the syntax for creating a frozenset

    The correct syntax uses the function frozenset() with an iterable inside parentheses.
  2. Step 2: Evaluate each option

    fs = frozenset([1, 2, 3]) uses frozenset with a list inside parentheses, which is correct. fs = frozen_set([1, 2, 3]) uses a wrong function name. fs = frozenset{1, 2, 3} uses curly braces which is invalid syntax for function calls. fs = frozenset(1, 2, 3) passes multiple arguments instead of one iterable.
  3. Final Answer:

    fs = frozenset([1, 2, 3]) -> Option A
  4. Quick Check:

    frozenset(iterable) = correct syntax [OK]
Hint: Use frozenset() with one iterable argument inside parentheses [OK]
Common Mistakes:
  • Using wrong function name like frozen_set
  • Using curly braces instead of parentheses
  • Passing multiple arguments instead of one iterable
3. What will be the output of this code?
fs = frozenset([1, 2, 2, 3])
print(len(fs))
medium
A. 4
B. Error
C. 3
D. 2

Solution

  1. Step 1: Understand frozenset removes duplicates

    The list has elements [1, 2, 2, 3]. When converted to frozenset, duplicates are removed, so it becomes {1, 2, 3}.
  2. Step 2: Calculate length of frozenset

    The frozenset has 3 unique elements, so len(fs) returns 3.
  3. Final Answer:

    3 -> Option C
  4. Quick Check:

    frozenset removes duplicates, length = 3 [OK]
Hint: Count unique elements only, duplicates are removed [OK]
Common Mistakes:
  • Counting duplicates as separate elements
  • Expecting an error due to duplicates
  • Confusing frozenset with list length
4. What is wrong with this code?
fs = frozenset([1, 2, 3])
fs.add(4)
print(fs)
medium
A. frozenset object has no attribute 'add'
B. It prints {1, 2, 3, 4}
C. It prints {1, 2, 3}
D. SyntaxError

Solution

  1. Step 1: Understand frozenset immutability

    frozenset objects cannot be changed after creation, so they do not have methods like add().
  2. Step 2: Identify the error when calling add()

    Calling fs.add(4) raises an AttributeError because 'frozenset' has no 'add' method.
  3. Final Answer:

    frozenset object has no attribute 'add' -> Option A
  4. Quick Check:

    frozenset is immutable, no add() method [OK]
Hint: frozenset has no add or remove methods [OK]
Common Mistakes:
  • Trying to add or remove elements from frozenset
  • Expecting frozenset to behave like set
  • Confusing AttributeError with SyntaxError
5. Given two frozensets:
fs1 = frozenset([1, 2, 3])
fs2 = frozenset([3, 4, 5])

Which expression correctly finds the common elements between fs1 and fs2?
hard
A. fs1 + fs2
B. fs1 & fs2
C. fs1 | fs2
D. fs1 - fs2

Solution

  1. Step 1: Recall set operations on frozensets

    frozensets support set operations like intersection (&), union (|), difference (-).
  2. Step 2: Identify operation for common elements

    The intersection operator & returns elements common to both sets. So fs1 & fs2 gives {3}.
  3. Final Answer:

    fs1 & fs2 -> Option B
  4. Quick Check:

    Intersection (&) = common elements [OK]
Hint: Use & operator to find common elements in frozensets [OK]
Common Mistakes:
  • Using + which is invalid for sets
  • Confusing union (|) with intersection
  • Using difference (-) instead of intersection