Dictionary comprehension with condition in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a dictionary with numbers as keys and their squares as values.

Python

squares = {x: x[1]2 for x in range(1, 6)}
print(squares)

Drag options to blanks, or click blank then click option'

A**

B+

C*

D//

Attempts:

3 left

💡 Hint

Common Mistakes

Using multiplication (*) instead of exponentiation (**).

Using addition (+) which adds numbers instead of squaring.

The ** operator is used to raise a number to a power. Here, x**2 means x squared.

2fill in blank

medium

Complete the code to create a dictionary of numbers and their squares only for numbers greater than 3.

Python

filtered_squares = {x: x**2 for x in range(1, 7) if x [1] 3}
print(filtered_squares)

Drag options to blanks, or click blank then click option'

A==

B!=

C>

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using less than (<) which selects numbers smaller than 3.

Using equality (==) which selects only number 3.

The condition x > 3 filters numbers greater than 3.

3fill in blank

hard

Fix the error in the dictionary comprehension to include only even numbers and their squares.

Python

even_squares = {n: n**2 for n in range(1, 10) if n [1] 2 == 0}
print(even_squares)

Drag options to blanks, or click blank then click option'

A//

B%

C*

D**

Attempts:

3 left

💡 Hint

Common Mistakes

Using floor division (//) which does not check for evenness.

Using multiplication (*) or exponentiation (**) which are unrelated.

The modulo operator % gives the remainder. n % 2 == 0 checks if n is even.

4fill in blank

hard

Fill both blanks to create a dictionary of words and their lengths only if the length is greater than 4.

Python

word_lengths = {word: [1] for word in words if len(word) [2] 4}

Drag options to blanks, or click blank then click option'

Alen(word)

Bword

C>

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as value instead of its length.

Using less than or equal (<=) which selects shorter words.

The value should be the length of the word using len(word). The condition should check if length is greater than 4 using >.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase words as keys and their lengths as values, only for words longer than 3 letters.

Python

result = { [1]: [2] for word in words if len(word) [3] 3 }

Drag options to blanks, or click blank then click option'

Aword.upper()

Blen(word)

C>

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using the original word as key instead of uppercase.

Using less than or equal (<=) which includes shorter words.

The key should be the uppercase word using word.upper(). The value is the length len(word). The condition filters words longer than 3 using >.