abs() and round() in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to get the absolute value of -7.

Python

result = [1](-7)
print(result)

Drag options to blanks, or click blank then click option'

Astr

Bround

Cint

Dabs

Attempts:

3 left

💡 Hint

Common Mistakes

Using round() instead of abs() will not remove the minus sign.

Using int() or str() won't change the sign of the number.

The abs() function returns the absolute value of a number, which means it makes negative numbers positive.

2fill in blank

medium

Complete the code to round the number 3.14159 to 2 decimal places.

Python

result = round(3.14159, [1])
print(result)

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A2

B1

C3

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0 will round to the nearest whole number.

Using 1 or 3 will round to the wrong number of decimals.

The round() function rounds a number to the specified number of decimal places. Here, 2 means two digits after the decimal point.

3fill in blank

hard

Fix the error in the code to correctly round the number 5.6789 without decimals.

Python

result = round([1])
print(result)

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Around(5.6789)

B'5.6789'

C5.6789

Dint(5.6789)

Attempts:

3 left

💡 Hint

Common Mistakes

Passing a string instead of a number causes an error.

Calling round() inside round() is incorrect.

The round() function needs a number as input, not a string or another function call inside.

4fill in blank

hard

Fill both blanks to create a dictionary with words as keys and their absolute length difference from 4 as values.

Python

words = ['cat', 'house', 'dog', 'tree']
length_diff = {word: abs(len(word) [1] 4) for word in words if len(word) [2] 2}
print(length_diff)

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A-

B+

C>

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+' instead of '-' changes the meaning.

Using '<' instead of '>' filters the wrong words.

The code calculates the absolute difference between the length of each word and 4, but only for words longer than 2 characters.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase words as keys, their rounded lengths as values, only if length is greater than 3.

Python

words = ['apple', 'bat', 'carrot', 'dog']
result = { [1]: round(len(word), [2]) for word in words if len(word) [3] 3 }
print(result)

Drag options to blanks, or click blank then click option'

Aword.upper()

B1

C>

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using word.lower() instead of uppercase keys.

Using '<' instead of '>' filters wrong words.

Rounding to 0 decimals changes output meaning.

The dictionary keys are uppercase words, values are lengths rounded to 1 decimal (though lengths are integers), and only words longer than 3 are included.