Logical operators in conditions in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if a number is positive and less than 10.

Python

if num > 0 [1] num < 10:
    print("Number is between 1 and 9")

Drag options to blanks, or click blank then click option'

Aand

Bor

Cnot

Dxor

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'or' instead of 'and' which allows numbers outside the range.

Using 'not' which negates a condition incorrectly.

The and operator checks if both conditions are true.

2fill in blank

medium

Complete the code to check if a character is a vowel or a digit.

Python

if char in 'aeiou' [1] char.isdigit():
    print("It's a vowel or a digit")

Drag options to blanks, or click blank then click option'

Aand

Bxor

Cnot

Dor

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'and' which requires both conditions to be true.

Using 'not' which negates a condition incorrectly.

The or operator checks if either condition is true.

3fill in blank

hard

Fix the error in the condition to check if a number is not between 5 and 15.

Python

if num < 5 [1] num > 15:
    print("Number is outside 5 to 15")

Drag options to blanks, or click blank then click option'

Aand

Bor

Cxor

Dnot

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'and' which would never be true because a number can't be less than 5 and greater than 15 at the same time.

To check if a number is outside the range, use or between the two conditions.

4fill in blank

hard

Fill both blanks to create a dictionary of words with length greater than 3 and containing letter 'a'.

Python

result = {word: len(word) for word in words if len(word) [1] 3 [2] 'a' in word}

Drag options to blanks, or click blank then click option'

A>

B<

Cand

Dor

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' for length comparison.

Using 'or' which includes words that don't meet both conditions.

We want words longer than 3 and containing 'a'.

5fill in blank

hard

Fill all three blanks to create a dictionary of uppercase keys and values for words longer than 4 or containing 'e'.

Python

result = [1]: [2] for word in words if len(word) [3] 4 or 'e' in word

Drag options to blanks, or click blank then click option'

Aword.upper()

Bword

C>

Dlen(word)

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'len(word)' as a key or value instead of the word itself.

Using '<' instead of '>' in the condition.

Keys are uppercase words, values are original words, and condition checks length > 4 or contains 'e'.