Logical operators in conditions in Python - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of combined logical operators

What is the output of this Python code snippet?

Python

x = 5
if x > 3 and not x == 5:
    print("A")
elif x > 3 or x == 5:
    print("B")
else:
    print("C")

A B

B SyntaxError

C C

D A

💡 Hint

Remember how 'and', 'or', and 'not' work together in conditions.

The first condition checks if x > 3 and x is not 5. Since x is 5, 'not x == 5' is False, so the first if fails. The elif checks if x > 3 or x == 5, which is True, so it prints 'B'.

❓ Predict Output

intermediate

Evaluating multiple logical conditions

What will be printed by this code?

Python

a = True
b = False
c = True
if a and b or c:
    print("Yes")
else:
    print("No")

A RuntimeError

B No

C SyntaxError

D Yes

💡 Hint

Remember the precedence of 'and' over 'or'.

The expression 'a and b or c' is evaluated as '(a and b) or c'. Since a and b is False, but c is True, the overall condition is True, so it prints 'Yes'.

❓ Predict Output

advanced

Output with mixed logical operators and parentheses

What is the output of this code?

Python

x = 10
if (x < 5 or x > 8) and not (x == 10):
    print("First")
elif x == 10 and not (x < 5):
    print("Second")
else:
    print("Third")

A First

B Second

C Third

D SyntaxError

💡 Hint

Check each condition carefully with parentheses.

The first if condition is False because although (x < 5 or x > 8) is True, 'not (x == 10)' is False. The elif condition is True because x == 10 and not (x < 5) is True, so it prints 'Second'.

❓ Predict Output

advanced

Logical operators with short-circuit behavior

What will this code print?

Python

def check():
    print("Checked")
    return False

if False and check():
    print("Yes")
else:
    print("No")

A No

B

Checked
Yes

C

Checked
No

D SyntaxError

💡 Hint

Remember how 'and' stops evaluating if the first part is False.

Because the first part of 'and' is False, Python does not call check(), so 'Checked' is not printed. The else block runs and prints 'No'.

❓ Predict Output

expert

Complex logical condition output

What is the output of this code?

Python

x = 3
y = 4
z = 5
if (x > y or y < z) and not (x == 3 and z == 5):
    print("Alpha")
elif x == 3 and (y == 4 or z == 6):
    print("Beta")
else:
    print("Gamma")

A Alpha

B Gamma

C Beta

D SyntaxError

💡 Hint

Evaluate each part step by step, especially the 'not' condition.

The first if condition is False because although (x > y or y < z) is True, the 'not (x == 3 and z == 5)' is False (since x==3 and z==5 is True). The elif condition is True because x==3 and (y==4 or z==6) is True, so it prints 'Beta'.