Python - Conditional Statements
You want to write a program that prints 'Even' if a number is even, and 'Odd' if it is odd. Which code correctly uses if-else to do this?
You want to write a program that prints 'Even' if a number is even, and 'Odd' if it is odd. Which code correctly uses if-else to do this?
hard📝 Application Q15 of 15
Step-by-Step Solution
Solution:
Step 1: Understand how to check even numbers
A number is even if dividing by 2 leaves no remainder, so num % 2 == 0 is true for even numbers.Step 2: Check each option's condition
num = 4 if num % 2 == 0: print('Even') else: print('Odd') correctly uses num % 2 == 0. num = 4 if num / 2 == 0: print('Even') else: print('Odd') uses division instead of modulo, which is wrong. num = 4 if num % 2: print('Even') else: print('Odd') treats nonzero remainder as even, which is incorrect. num = 4 if num % 2 != 0: print('Even') else: print('Odd') reverses the logic.Final Answer:
num = 4 if num % 2 == 0: print('Even') else: print('Odd') -> Option DQuick Check:
Modulo equals zero means even [OK]
Quick Trick: Use 'num % 2 == 0' to check even numbers [OK]
Common Mistakes:
MISTAKES- Using division instead of modulo
- Reversing even and odd logic
- Checking truthiness of modulo without comparison
Master "Conditional Statements" in Python
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