[Solved] Given this dictionary:status = {"a": True, "b": False, "c": 0, "d": "1"}Which code returns a list of keys with truthy values? | Python

Python - Data Types as Values

Given this dictionary:

status = {"a": True, "b": False, "c": 0, "d": "1"}

Which code returns a list of keys with truthy values?

A[k for k, v in status.items() if v]

B[k for k, v in status.items() if v == True]

C[k for k, v in status.items() if bool(k)]

D[k for k, v in status.items() if v is True]

Step-by-Step Solution

Solution:

Step 1: Understand filtering dictionary by truthy values
We want keys where the value is truthy (non-zero, True, non-empty).
Step 2: Evaluate each option
[k for k, v in status.items() if v] filters by 'if v' which keeps True and "1" but excludes False and 0. [k for k, v in status.items() if v == True] keeps only values == True (excludes "1"). [k for k, v in status.items() if bool(k)] filters by key truthiness, not value. [k for k, v in status.items() if v is True] keeps only values that are exactly True (excludes "1").
Final Answer:
[k for k, v in status.items() if v] -> Option A
Quick Check:
Filter dict by 'if v' for truthy values [OK]

Quick Trick: Use 'if v' to filter truthy dict values in comprehension [OK]

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