If–else execution flow in Python - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of nested if–else blocks

What is the output of this Python code?

Python

x = 10
if x > 5:
    if x > 15:
        print("A")
    else:
        print("B")
else:
    print("C")

A B

B C

C A

D No output

💡 Hint

Check the conditions step by step, starting from the outer if.

The variable x is 10, which is greater than 5, so the outer if is true.

Then the inner if checks if x is greater than 15, which is false.

So the else of the inner block runs, printing "B".

❓ Predict Output

intermediate

If–else with multiple conditions

What will be printed by this code?

Python

score = 75
if score >= 90:
    print("Excellent")
elif score >= 70:
    print("Good")
else:
    print("Try again")

A Excellent

B No output

C Try again

D Good

💡 Hint

Check which condition matches the score first.

The score is 75.

The first condition score >= 90 is false.

The second condition score >= 70 is true, so it prints "Good".

❓ Predict Output

advanced

If–else with assignment expressions

What is the output of this code using the walrus operator?

Python

if (n := 4) > 3:
    print(f"Number {n} is greater than 3")
else:
    print(f"Number {n} is not greater than 3")

A Number 4 is greater than 3

B Number 4 is not greater than 3

C No output

D SyntaxError

💡 Hint

The walrus operator assigns and returns the value in the condition.

The walrus operator n := 4 assigns 4 to n and returns 4.

Since 4 > 3 is true, it prints "Number 4 is greater than 3".

❓ Predict Output

advanced

If–else with match-case and else

What will this code print?

Python

value = 2
match value:
    case 1:
        print("One")
    case 2:
        print("Two")
    case _:
        print("Other")

A One

B Two

C Other

D SyntaxError

💡 Hint

The match-case checks the value against each case.

The variable value is 2.

The case 2 matches, so it prints "Two".

❓ Predict Output

expert

Complex if–else with multiple conditions and logical operators

What is the output of this code?

Python

a = 5
b = 10
if a > 0 and b < 5:
    print("X")
elif a > 0 or b < 5:
    print("Y")
else:
    print("Z")

A Z

B X

C Y

D No output

💡 Hint

Evaluate each condition carefully with the values of a and b.

a is 5 (greater than 0), b is 10 (not less than 5).

The first condition a > 0 and b < 5 is false because b < 5 is false.

The second condition a > 0 or b < 5 is true because a > 0 is true.

So it prints "Y".