[Solved] Which of the following is the correct syntax for an if-else statement in Python? — Ans: if x > 0: print('Positive') else: print('Non-positive') | Python

Python - Conditional Statements

Which of the following is the correct syntax for an if-else statement in Python?

Aif x > 0: print('Positive') else: print('Non-positive')

Bif x > 0 then print('Positive') else print('Non-positive')

Cif (x > 0) { print('Positive'); } else { print('Non-positive'); }

Dif x > 0 print('Positive') else print('Non-positive')

Step-by-Step Solution

Solution:

Step 1: Recall Python if-else syntax
Python uses a colon after the condition and indentation for the code blocks.
Step 2: Check each option
if x > 0: print('Positive') else: print('Non-positive') uses colons and indentation correctly. if x > 0 then print('Positive') else print('Non-positive') uses 'then' which is not Python syntax. if (x > 0) { print('Positive'); } else { print('Non-positive'); } uses braces and semicolons, which are for other languages. if x > 0 print('Positive') else print('Non-positive') misses colons and indentation.
Final Answer:
if x > 0: print('Positive') else: print('Non-positive') -> Option A
Quick Check:
Colon + indent = correct if-else [OK]

Quick Trick: Remember colons and indentation for if-else in Python [OK]

Common Mistakes:

MISTAKES

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Which of the following is the correct syntax for an if-else statement in Python?