How can you use a for-else loop to find if a list contains any negative numbers and print Found negative or No negatives accordingly?
hard📝 Application Q9 of 15
Python - For Loop
How can you use a for-else loop to find if a list contains any negative numbers and print Found negative or No negatives accordingly?
Afor num in lst:
if num < 0:
print('Found negative')
else:
print('No negatives')
Bfor num in lst:
if num < 0:
print('No negatives')
break
else:
print('Found negative')
Cfor num in lst:
if num >= 0:
print('Found negative')
break
else:
print('No negatives')
Dfor num in lst:
if num < 0:
print('Found negative')
break
else:
print('No negatives')
Step-by-Step Solution
Solution:
Step 1: Detect negative numbers with break
Loop through list, if a negative is found, print 'Found negative' and break.
Step 2: Use else to print if no break
If loop finishes without break, print 'No negatives' in else block. for num in lst:
if num < 0:
print('Found negative')
break
else:
print('No negatives') matches this logic.
Final Answer:
for num in lst:
if num < 0:
print('Found negative')
break
else:
print('No negatives') -> Option D
Quick Check:
Break on negative, else means none found [OK]
Quick Trick:Break on condition met, else means condition never met [OK]
Common Mistakes:
MISTAKES
Swapping messages for found and not found
Missing break causing multiple prints
Placing else inside loop incorrectly
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