For–else execution behavior in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print "Found" if 3 is in the list, otherwise print "Not found".

Python

numbers = [1, 2, 3, 4, 5]
for num in numbers:
    if num == [1]:
        print("Found")
        break
else:
    print("Not found")

Drag options to blanks, or click blank then click option'

A3

B4

C5

D2

Attempts:

3 left

💡 Hint

Common Mistakes

Using a number not in the list, so the else block always runs.

Forgetting to use break to stop the loop when found.

The loop checks each number. When it finds 3, it prints "Found" and stops. The else runs only if the loop never breaks.

2fill in blank

medium

Complete the code to print "No even number" if no even number is found in the list.

Python

nums = [1, 3, 5, 7]
for n in nums:
    if n % [1] == 0:
        print("Even number found")
        break
else:
    print("No even number")

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A3

B4

C5

D2

Attempts:

3 left

💡 Hint

Common Mistakes

Using a divisor other than 2, so the condition never matches.

Not using modulo operator correctly.

Even numbers are divisible by 2. The code checks if any number is divisible by 2. If none are, the else block runs.

3fill in blank

hard

Fix the error in the code to correctly print "Found" if 0 is in the list, else "Not found".

Python

values = [1, 2, 3, 4]
for val in values:
    if val == [1]:
        print("Found")
        break
else:
    print("Not found")

Drag options to blanks, or click blank then click option'

A0

B4

C5

D3

Attempts:

3 left

💡 Hint

Common Mistakes

Using a number that is actually in the list, which does not match the task.

Not understanding the else block runs only if break never happens.

The code looks for 0, but 0 is not in the list. Fixing the value to 0 makes the condition correct for the task.

4fill in blank

hard

Fill both blanks to create a dictionary of squares for numbers greater than 2.

Python

squares = {x: x[1]2 for x in range(1, 6) if x [2] 2}
print(squares)

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A**

B>

C<

D*

Attempts:

3 left

💡 Hint

Common Mistakes

Using multiplication (*) instead of exponentiation (**).

Using less than (<) instead of greater than (>) in the condition.

The code uses exponentiation (**) to square numbers. The condition x > 2 filters numbers greater than 2.

5fill in blank

hard

Fill all three blanks to create a dictionary of uppercase keys and values greater than 1.

Python

result = [1]: [2] for k, v in data.items() if v [3] 1
print(result)

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Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Using k instead of k.upper() for keys.

Using < instead of > in the condition.

Swapping keys and values.

The keys are converted to uppercase with k.upper(). Values are kept as v. The condition filters values greater than 1.