[Solved] What is the output of this code?for num in [1, 2, 3]: if num == 4: break else: print("No break encountered") | Python

Python - For Loop

What is the output of this code?

for num in [1, 2, 3]:
    if num == 4:
        break
else:
    print("No break encountered")

ANo output

BNo break encountered

Cbreak

DError

Step-by-Step Solution

Solution:

Step 1: Analyze the loop and condition
The loop checks if num == 4. Since 4 is not in the list, break never runs.
Step 2: Check the else block execution
Because the loop completes without break, the else block runs and prints "No break encountered".
Final Answer:
No break encountered -> Option B
Quick Check:
Else runs if no break, so prints message [OK]

Quick Trick: Else runs only if break never happens [OK]

Common Mistakes:

MISTAKES

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