[Solved] You want to stop searching a list as soon as you find the number 7. Which code correctly uses break to do this?numbers = [3, 5, 7, 9, 11] for num in numbers: # Your code here | Python

Python - Loop Control

You want to stop searching a list as soon as you find the number 7. Which code correctly uses break to do this?

numbers = [3, 5, 7, 9, 11]
for num in numbers:
    # Your code here

Aprint(num) if num == 7: break

Bif num == 7: break print(num)

Cif num != 7: break print(num)

Dbreak if num == 7 print(num)

Step-by-Step Solution

Solution:

Step 1: Understand the goal
We want to print numbers until we find 7, then stop immediately.
Step 2: Check each option's logic
print(num) if num == 7: break prints the number first, then breaks if it is 7, stopping after printing 7.
Final Answer:
print(num)\nif num == 7:\n break -> Option A
Quick Check:
Print then break on 7 = print(num) if num == 7: break [OK]

Quick Trick: Print before break to include the break value [OK]

Common Mistakes:

MISTAKES

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You want to stop searching a list as soon as you find the number 7. Which code correctly uses break to do this?