Break statement behavior in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to stop the loop when the number 3 is found.

Python

for num in range(5):
    if num == 3:
        [1]
    print(num)

Drag options to blanks, or click blank then click option'

Abreak

Breturn

Cpass

Dcontinue

Attempts:

3 left

💡 Hint

Common Mistakes

Using continue instead of break, which skips the rest of the loop but does not stop it.

Using pass, which does nothing and continues the loop.

The break statement stops the loop immediately when the condition is met.

2fill in blank

medium

Complete the code to exit the while loop when count reaches 5.

Python

count = 0
while True:
    print(count)
    count += 1
    if count == 5:
        [1]

Drag options to blanks, or click blank then click option'

Aexit

Bcontinue

Cbreak

Dstop

Attempts:

3 left

💡 Hint

Common Mistakes

Using continue, which skips to the next iteration but does not stop the loop.

Using exit or stop, which are not valid Python statements for loops.

The break statement exits the loop when count equals 5.

3fill in blank

hard

Complete the code to stop the loop when the letter 'a' is found.

Python

letters = ['b', 'c', 'a', 'd']
for letter in letters:
    if letter == 'a':
        [1]
    print(letter)

Drag options to blanks, or click blank then click option'

Acontinue

Breturn

Cpass

Dbreak

Attempts:

3 left

💡 Hint

Common Mistakes

Using continue instead of break, which does not stop the loop.

The break statement stops the loop when 'a' is found.

4fill in blank

hard

Fill both blanks to create a loop that prints numbers until it reaches 4, then stops.

Python

for i in range(10):
    print(i)
    if i [1] 4:
        [2]

Drag options to blanks, or click blank then click option'

A==

B<

Cbreak

Dcontinue

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '==' in the condition.

Using continue instead of break, which skips but does not stop the loop.

The condition i == 4 checks when i is 4, and break stops the loop at that point.

5fill in blank

hard

Fill all three blanks to create a loop that prints only numbers less than 5 and stops when it reaches 7.

Python

for num in range(10):
    if num [1] 7:
        [2]
    if num [3] 5:
        print(num)

Drag options to blanks, or click blank then click option'

A>=

Bbreak

C<

Dcontinue

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong comparison operators.

Using continue instead of break to stop the loop.

The first condition checks if num >= 7. The break stops the loop at 7. The last condition prints numbers less than 5.

Practice

1.

What does the break statement do inside a loop?

easy

A. Restarts the loop from the beginning

B. Skips the current iteration and continues with the next

C. Stops the loop immediately and exits it

D. Pauses the loop for a moment

Solution

1. Step 1: Understand the purpose of break

   The break statement is designed to stop the loop immediately when executed.

2. Step 2: Compare with other loop controls

   Unlike continue which skips to the next iteration, break exits the loop entirely.

3. Final Answer:

   Stops the loop immediately and exits it -> Option C

4. Quick Check:

   Break stops loop = A [OK]

Hint: Break means stop loop now, not skip or pause [OK]

Common Mistakes:

• Confusing break with continue
• Thinking break pauses instead of stops
• Believing break restarts the loop

2.

Which of the following is the correct syntax to use break inside a for loop?

for i in range(5):
    ___
    print(i)

easy

A. break if i == 3

B. if i == 3: break

C. break: if i == 3

D. if break i == 3

Solution

1. Step 1: Recall correct Python syntax for conditions

   Python uses if condition: followed by indented code.

2. Step 2: Place break inside the if block

   The correct way is if i == 3: break to stop loop when i equals 3.

3. Final Answer:

   if i == 3: break -> Option B

4. Quick Check:

   Correct if-break syntax = C [OK]

Hint: Use 'if condition: break' inside loops [OK]

Common Mistakes:

• Writing break before if
• Using colon after break
• Incorrect order of if and break

3.

What is the output of this code?

for i in range(5):
    if i == 2:
        break
    print(i)

medium

A. 0 1 2 3 4

B. 0 1 2

C. 2

D. 0 1

Solution

1. Step 1: Trace the loop iterations

   The loop runs i from 0 to 4. It prints i unless i == 2.

2. Step 2: Apply break when i == 2

   When i reaches 2, the break stops the loop immediately, so 2 is not printed.

3. Final Answer:

   0 1 -> Option D

4. Quick Check:

   Loop stops before printing 2 = A [OK]

Hint: Break stops before printing the break condition value [OK]

Common Mistakes:

• Including the break value in output
• Ignoring break and printing all
• Confusing break with continue

4.

Find the error in this code snippet:

i = 0
while i < 5:
    if i == 3
        break
    print(i)
    i += 1

medium

A. Missing colon after if condition

B. Break cannot be used in while loops

C. Variable i is not incremented

D. Print statement is outside the loop

Solution

1. Step 1: Check syntax of if statement

   The if statement must end with a colon (:). Here it is missing.

2. Step 2: Verify other parts

   Break is allowed in while loops, i is incremented, and print is inside the loop.

3. Final Answer:

   Missing colon after if condition -> Option A

4. Quick Check:

   Syntax error due to missing colon = D [OK]

Hint: If statements always need a colon at the end [OK]

Common Mistakes:

• Forgetting colon after if
• Thinking break is invalid in while
• Ignoring indentation errors

5.

Given this nested loop, what will be the output?

for i in range(3):
    for j in range(3):
        if j == 1:
            break
        print(f"{i},{j}")

hard

A. "0,0" "1,0" "2,0"

B. "0,0" "0,1" "1,0" "1,1" "2,0" "2,1"

C. "0,0" "0,1" "1,0" "2,0"

D. "0,0" "0,1" "1,0" "1,1" "2,0"

Solution

1. Step 1: Understand nested loops and break

   The inner loop runs j from 0 to 2. When j == 1, break stops inner loop.

2. Step 2: Trace printed values

   For each i, only j=0 prints before break stops inner loop. So outputs are "0,0", "1,0", "2,0".

3. Final Answer:

   "0,0" "1,0" "2,0" -> Option A

4. Quick Check:

   Break stops inner loop at j=1 = B [OK]

Hint: Break stops only inner loop, outer continues [OK]

Common Mistakes:

• Thinking break stops both loops
• Including j=1 in output
• Confusing loop variables