[Solved] Write code to count how many vowels are in the string sentence. Which code correctly does this? — Ans: count = 0 for ch in sentence: if ch in 'aeiouAEIOU': count += 1 print(count) | Python

Python - For Loop

Write code to count how many vowels are in the string sentence. Which code correctly does this?

Acount = 0 for ch in sentence: if ch in 'aeiouAEIOU': count += 1 print(count)

Bcount = 0 for i in range(len(sentence)): if sentence[i] == 'aeiou': count += 1 print(count)

Ccount = 0 for ch in sentence: if ch == 'a' or 'e' or 'i' or 'o' or 'u': count += 1 print(count)

Dcount = 0 for ch in sentence: if ch in ['a','e','i','o','u']: count = count + 1 print(count)

Step-by-Step Solution

Solution:

Step 1: Check vowel membership correctly
count = 0 for ch in sentence: if ch in 'aeiouAEIOU': count += 1 print(count) checks if each character is in the string of vowels (both lowercase and uppercase), which is correct.
Step 2: Verify counting logic
count = 0 for ch in sentence: if ch in 'aeiouAEIOU': count += 1 print(count) increments count correctly when a vowel is found and prints the total count.
Final Answer:
count = 0 for ch in sentence: if ch in 'aeiouAEIOU': count += 1 print(count) -> Option A
Quick Check:
Use 'in' with vowel string and increment count [OK]

Quick Trick: Use 'if ch in "aeiouAEIOU"' to check vowels [OK]

Common Mistakes:

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Write code to count how many vowels are in the string sentence. Which code correctly does this?