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PostgreSQLquery~5 mins

Hash partitioning for distribution in PostgreSQL - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What is hash partitioning in a database?
Hash partitioning is a method of dividing a table into smaller parts (partitions) based on a hash function applied to a column's values. This helps distribute data evenly across partitions.
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beginner
How does hash partitioning help with data distribution?
Hash partitioning uses a hash function to assign rows to partitions, ensuring data is spread evenly. This improves query performance and balances storage and workload.
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intermediate
In PostgreSQL, how do you create a hash partitioned table?
You create a partitioned table with PARTITION BY HASH(column_name), then create partitions with FOR VALUES WITH (MODULUS n, REMAINDER r) to specify which rows go where.
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intermediate
What is the role of MODULUS and REMAINDER in PostgreSQL hash partitions?
MODULUS defines the total number of partitions, and REMAINDER specifies which partition a row belongs to based on the hash value modulo MODULUS.
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intermediate
Why might hash partitioning be preferred over range partitioning?
Hash partitioning evenly distributes data regardless of value ranges, which is useful when data is uniformly accessed or when range boundaries are hard to define.
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What does hash partitioning use to assign rows to partitions?
AA hash function on a column's value
BA range of values
CThe row insertion time
DThe primary key order
In PostgreSQL, which clause specifies hash partitioning when creating a table?
APARTITION BY COLUMN(column_name)
BPARTITION BY RANGE(column_name)
CPARTITION BY HASH(column_name)
DPARTITION BY LIST(column_name)
What does the MODULUS value represent in PostgreSQL hash partitions?
AThe hash function used
BThe partition number for a row
CThe maximum size of a partition
DThe total number of partitions
Which of these is a benefit of hash partitioning?
ASorting data alphabetically
BEven data distribution across partitions
CGrouping data by date ranges
DStoring data in a single partition
If you want to partition a table into 4 parts using hash partitioning, what should MODULUS be set to?
A4
B2
C1
D8
Explain how hash partitioning works and why it is useful for distributing data.
Think about how a hash function assigns rows to different partitions.
You got /4 concepts.
    Describe the steps to create a hash partitioned table in PostgreSQL and how partitions are defined.
    Focus on the syntax and meaning of MODULUS and REMAINDER.
    You got /4 concepts.

      Practice

      (1/5)
      1. What is the main purpose of hash partitioning in PostgreSQL?
      easy
      A. To split data into parts using a hash function on a column
      B. To sort data alphabetically in each partition
      C. To store data only on one server
      D. To encrypt data for security

      Solution

      1. Step 1: Understand hash partitioning concept

        Hash partitioning divides data by applying a hash function to a column value, distributing rows into partitions.
      2. Step 2: Compare options with concept

        Only To split data into parts using a hash function on a column correctly describes this purpose; others describe unrelated features.
      3. Final Answer:

        To split data into parts using a hash function on a column -> Option A
      4. Quick Check:

        Hash partitioning = split data by hash [OK]
      Hint: Hash partitioning splits data by hashing a column [OK]
      Common Mistakes:
      • Confusing hash partitioning with sorting
      • Thinking it stores data on one server only
      • Mixing partitioning with encryption
      2. Which of the following is the correct syntax to create a hash partitioned table in PostgreSQL?
      easy
      A. CREATE TABLE sales PARTITION BY COLUMN (region);
      B. CREATE TABLE sales PARTITION BY RANGE (region);
      C. CREATE TABLE sales PARTITION BY LIST (region);
      D. CREATE TABLE sales PARTITION BY HASH (region);

      Solution

      1. Step 1: Identify partitioning syntax

        PostgreSQL uses PARTITION BY HASH(column) to create hash partitions.
      2. Step 2: Match syntax with options

        Only CREATE TABLE sales PARTITION BY HASH (region); uses PARTITION BY HASH correctly; others use different partition types or invalid syntax.
      3. Final Answer:

        CREATE TABLE sales PARTITION BY HASH (region); -> Option D
      4. Quick Check:

        Hash partition syntax = PARTITION BY HASH [OK]
      Hint: Use PARTITION BY HASH(column) for hash partitioning [OK]
      Common Mistakes:
      • Using RANGE or LIST instead of HASH
      • Writing PARTITION BY COLUMN which is invalid
      • Omitting parentheses around column
      3. Given the table definition:
      CREATE TABLE users (id INT, name TEXT) PARTITION BY HASH (id);
      CREATE TABLE users_p0 PARTITION OF users FOR VALUES WITH (MODULUS 4, REMAINDER 0);
      CREATE TABLE users_p1 PARTITION OF users FOR VALUES WITH (MODULUS 4, REMAINDER 1);
      CREATE TABLE users_p2 PARTITION OF users FOR VALUES WITH (MODULUS 4, REMAINDER 2);
      CREATE TABLE users_p3 PARTITION OF users FOR VALUES WITH (MODULUS 4, REMAINDER 3);

      Which partition will the row with id = 7 be stored in?
      medium
      A. users_p3
      B. users_p1
      C. users_p2
      D. users_p0

      Solution

      1. Step 1: Calculate hash partition remainder

        Partition is chosen by (hash(id) % modulus). Assuming hash(id) = id for simplicity, 7 % 4 = 3.
      2. Step 2: Match remainder to partition

        Remainder 3 corresponds to partition users_p3.
      3. Final Answer:

        users_p3 -> Option A
      4. Quick Check:

        7 % 4 = 3 -> users_p3 [OK]
      Hint: Compute id % modulus to find partition remainder [OK]
      Common Mistakes:
      • Confusing remainder with modulus
      • Using id directly without modulo
      • Mixing partition numbers
      4. You try to create a hash partition with this command:
      CREATE TABLE orders_p0 PARTITION OF orders FOR VALUES WITH (MODULUS 3, REMAINDER 3);

      What is the error in this statement?
      medium
      A. MODULUS must be a prime number
      B. REMAINDER cannot be equal to or greater than MODULUS
      C. Partition name must start with 'orders_'
      D. FOR VALUES WITH is not valid syntax for hash partitions

      Solution

      1. Step 1: Understand modulus and remainder rules

        Remainder must be less than modulus because remainder is result of modulo operation.
      2. Step 2: Check given values

        MODULUS is 3, REMAINDER is 3, which is invalid since remainder must be 0, 1, or 2.
      3. Final Answer:

        REMAINDER cannot be equal to or greater than MODULUS -> Option B
      4. Quick Check:

        Remainder < Modulus rule violated [OK]
      Hint: Remainder must be less than modulus in partitions [OK]
      Common Mistakes:
      • Setting remainder equal to modulus
      • Thinking modulus must be prime
      • Misunderstanding syntax for hash partitions
      5. You want to distribute a large logs table by hashing the user_id column into 5 partitions. Which of the following is the correct way to define the partitions?
      hard
      A. Create 5 partitions with MODULUS 6 and REMAINDER values from 0 to 5
      B. Create 5 partitions with MODULUS 4 and REMAINDER values from 0 to 4
      C. Create 5 partitions with MODULUS 5 and REMAINDER values from 0 to 4
      D. Create 5 partitions with MODULUS 5 and REMAINDER values from 1 to 5

      Solution

      1. Step 1: Understand modulus and remainder for partitions

        MODULUS is total partitions count; REMAINDER ranges from 0 to MODULUS-1.
      2. Step 2: Apply to 5 partitions

        MODULUS must be 5; REMAINDER values must be 0,1,2,3,4 for 5 partitions.
      3. Final Answer:

        Create 5 partitions with MODULUS 5 and REMAINDER values from 0 to 4 -> Option C
      4. Quick Check:

        Partitions = MODULUS 5, REMAINDER 0-4 [OK]
      Hint: Use MODULUS = partitions count; REMAINDER from 0 to MODULUS-1 [OK]
      Common Mistakes:
      • Setting remainder range incorrectly
      • Using wrong modulus number
      • Starting remainder at 1 instead of 0