Self join patterns in PostgreSQL - Mini Project: Build & Apply

Self Join Patterns in PostgreSQL

📖 Scenario: You work in a company database where employees have managers who are also employees. You want to find pairs of employees and their managers using a self join.

🎯 Goal: Build a PostgreSQL query using a self join to list each employee with their manager's name.

📋 What You'll Learn

Create a table called employees with columns id, name, and manager_id

Insert exact employee data with specified IDs and manager relationships

Write a self join query joining employees to itself using manager_id

Select employee names and their manager names in the result

💡 Why This Matters

🌍 Real World

Companies often store employee-manager relationships in the same table. Self joins help retrieve hierarchical data like reporting lines.

💼 Career

Understanding self joins is essential for database roles involving organizational data, reporting structures, and recursive relationships.

1

Create the employees table

Write a SQL statement to create a table called employees with columns id as integer primary key, name as text, and manager_id as integer that can be null.

PostgreSQL

-- Create the employees table with id, name, and manager_id columns
-- Your code here

Hint

Use CREATE TABLE with three columns: id, name, and manager_id. The id should be the primary key.

2

Insert employee data

Insert these exact rows into employees: (1, 'Alice', NULL), (2, 'Bob', 1), (3, 'Charlie', 1), (4, 'Diana', 2).

PostgreSQL

CREATE TABLE employees (
    id INTEGER PRIMARY KEY,
    name TEXT NOT NULL,
    manager_id INTEGER
);
-- Insert the employee data below
-- Your code here

Hint

Use a single INSERT INTO employees statement with multiple rows.

3

Write the self join query

Write a SQL query that uses a self join on employees aliased as e and m where e.manager_id = m.id. Select e.name AS employee and m.name AS manager.

PostgreSQL

CREATE TABLE employees (
    id INTEGER PRIMARY KEY,
    name TEXT NOT NULL,
    manager_id INTEGER
);

INSERT INTO employees (id, name, manager_id) VALUES
(1, 'Alice', NULL),
(2, 'Bob', 1),
(3, 'Charlie', 1),
(4, 'Diana', 2);

-- Write the self join query below
-- Your code here

Hint

Use JOIN employees m ON e.manager_id = m.id to join employees to their managers.

4

Complete the query with ordering

Add an ORDER BY e.name clause at the end of the query to sort results by employee name.

PostgreSQL

CREATE TABLE employees (
    id INTEGER PRIMARY KEY,
    name TEXT NOT NULL,
    manager_id INTEGER
);

INSERT INTO employees (id, name, manager_id) VALUES
(1, 'Alice', NULL),
(2, 'Bob', 1),
(3, 'Charlie', 1),
(4, 'Diana', 2);

SELECT e.name AS employee, m.name AS manager
FROM employees e
JOIN employees m ON e.manager_id = m.id
-- Add ORDER BY clause below
-- Your code here

Hint

Use ORDER BY e.name to sort the output by employee name alphabetically.

Practice

1. What is the main purpose of using a self join in PostgreSQL?

easy

A. To join a table to itself to compare rows within the same table

B. To join two different tables based on a common column

C. To create a backup of a table

D. To delete duplicate rows from a table

Solution

1. Step 1: Understand the concept of self join

   A self join is used when you want to compare rows within the same table by joining the table to itself.

2. Step 2: Differentiate from other joins

   Other joins combine different tables, but self join works on one table with aliases to distinguish instances.

3. Final Answer:

   To join a table to itself to compare rows within the same table -> Option A

4. Quick Check:

   Self join = join table to itself [OK]

Hint: Self join means joining table to itself using aliases [OK]

Common Mistakes:

• Confusing self join with joining two different tables
• Thinking self join creates a new table
• Assuming self join deletes duplicates

2. Which of the following is the correct syntax to perform a self join on a table named employees with aliases e1 and e2?

easy

A. SELECT * FROM employees e1 LEFT JOIN employees e2 ON e1.id = e2.manager_id;

B. SELECT * FROM employees JOIN employees ON employees.manager_id = employees.id;

C. SELECT * FROM employees AS e1, employees AS e2 WHERE e1.id = e2.id;

D. SELECT * FROM employees e1 JOIN employees e2 ON e1.manager_id = e2.id;

Solution

1. Step 1: Identify correct alias usage

   Using aliases e1 and e2 for the same table employees is necessary to distinguish instances.

2. Step 2: Check join condition

   The join condition e1.manager_id = e2.id correctly links employees to their managers.

3. Final Answer:

   SELECT * FROM employees e1 JOIN employees e2 ON e1.manager_id = e2.id; -> Option D

4. Quick Check:

   Use aliases and proper ON condition [OK]

Hint: Use aliases and ON clause for self join syntax [OK]

Common Mistakes:

• Not using aliases causing ambiguity
• Wrong join condition columns
• Using comma join without ON clause

3. Given the table employees(id, name, manager_id) with data:

id | name  | manager_id
---+-------+-----------
1  | Alice | NULL
2  | Bob   | 1
3  | Carol | 1
4  | Dave  | 2

What will be the output of this query?

SELECT e1.name AS employee, e2.name AS manager
FROM employees e1
LEFT JOIN employees e2 ON e1.manager_id = e2.id
ORDER BY e1.id;

medium

A. [{"employee": "Alice", "manager": null}, {"employee": "Bob", "manager": null}, {"employee": "Carol", "manager": null}, {"employee": "Dave", "manager": null}]

B. [{"employee": "Alice", "manager": null}, {"employee": "Bob", "manager": "Alice"}, {"employee": "Carol", "manager": "Alice"}, {"employee": "Dave", "manager": "Bob"}]

C. [{"employee": "Alice", "manager": "Alice"}, {"employee": "Bob", "manager": "Bob"}, {"employee": "Carol", "manager": "Carol"}, {"employee": "Dave", "manager": "Dave"}]

D. [{"employee": "Alice", "manager": "Bob"}, {"employee": "Bob", "manager": "Carol"}, {"employee": "Carol", "manager": "Dave"}, {"employee": "Dave", "manager": null}]

Solution

1. Step 1: Understand the join logic

   The LEFT JOIN matches each employee's manager_id to the manager's id, returning manager's name or null if none.

2. Step 2: Map each employee to their manager

   Alice has no manager (null), Bob and Carol have Alice as manager, Dave has Bob as manager.

3. Final Answer:

   [{"employee": "Alice", "manager": null}, {"employee": "Bob", "manager": "Alice"}, {"employee": "Carol", "manager": "Alice"}, {"employee": "Dave", "manager": "Bob"}] -> Option B

4. Quick Check:

   LEFT JOIN matches manager_id to id [OK]

Hint: Match manager_id to id with LEFT JOIN for manager names [OK]

Common Mistakes:

• Confusing employee and manager columns
• Using INNER JOIN losing employees without managers
• Assuming manager_id is employee id

4. Consider this query intended to find pairs of employees who share the same manager:

SELECT e1.name, e2.name
FROM employees e1
JOIN employees e2 ON e1.manager_id = e2.manager_id
WHERE e1.id != e2.id;

What is the main issue with this query?

medium

A. It will return duplicate pairs in both orders (e.g., (Alice, Bob) and (Bob, Alice))

B. It will not return any rows because of the WHERE clause

C. It causes a syntax error due to missing aliases

D. It only returns employees with no manager

Solution

1. Step 1: Analyze join condition

   The join matches employees with the same manager_id, including reversed pairs.

2. Step 2: Check WHERE clause effect

   WHERE e1.id != e2.id avoids self-pairing but does not prevent duplicate pairs in reverse order.

3. Final Answer:

   It will return duplicate pairs in both orders (e.g., (Alice, Bob) and (Bob, Alice)) -> Option A

4. Quick Check:

   Self join can produce reversed duplicate pairs [OK]

Hint: Self join pairs may appear twice reversed; use filtering [OK]

Common Mistakes:

• Assuming WHERE clause removes duplicates
• Thinking query causes syntax error
• Believing it returns only employees without managers

5. You want to find all employees who are managers themselves, i.e., employees who have at least one other employee reporting to them. Which self join query correctly achieves this?

hard

A. SELECT e1.name FROM employees e1 JOIN employees e2 ON e1.manager_id = e2.id;

B. SELECT e1.name FROM employees e1 LEFT JOIN employees e2 ON e1.id = e2.manager_id WHERE e2.id IS NULL;

C. SELECT DISTINCT e1.name FROM employees e1 JOIN employees e2 ON e1.id = e2.manager_id;

D. SELECT e1.name FROM employees e1 WHERE e1.manager_id IS NOT NULL;

Solution

1. Step 1: Understand the requirement

   Managers are employees whose id appears as manager_id for others.

2. Step 2: Analyze each option

   SELECT DISTINCT e1.name FROM employees e1 JOIN employees e2 ON e1.id = e2.manager_id; joins employees where e1.id = e2.manager_id, selecting distinct managers correctly.

3. Final Answer:

   SELECT DISTINCT e1.name FROM employees e1 JOIN employees e2 ON e1.id = e2.manager_id; -> Option C

4. Quick Check:

   Join on id = manager_id finds managers [OK]

Hint: Join employees where id = manager_id to find managers [OK]

Common Mistakes:

• Using LEFT JOIN with IS NULL returns non-managers
• Joining on wrong columns (manager_id = id reversed)
• Filtering on manager_id IS NOT NULL returns employees with managers