FULL OUTER JOIN in PostgreSQL

Introduction

A FULL OUTER JOIN helps you combine rows from two tables, showing all matches and also rows that don't have a match in either table.

You want to see all customers and all orders, even if some customers have no orders and some orders have no customers.

You need to compare two lists and find which items are only in one list or the other, and which are in both.

You want to merge employee data from two departments, including employees unique to each department.

You want to find all products and their sales, including products that have never been sold and sales records without a product.

Syntax

PostgreSQL

SELECT columns
FROM table1
FULL OUTER JOIN table2
ON table1.common_column = table2.common_column;

FULL OUTER JOIN returns all rows from both tables.

If there is no match, columns from the other table will be NULL.

Examples

Shows all employees and all departments, matching where possible.

PostgreSQL

SELECT *
FROM employees
FULL OUTER JOIN departments
ON employees.department_id = departments.id;

Lists all orders and customers, even if some orders have no customer or some customers have no orders.

PostgreSQL

SELECT orders.id, customers.name
FROM orders
FULL OUTER JOIN customers
ON orders.customer_id = customers.id;

Sample Program

This query shows all students and their scores. It also shows scores for student_id 4, who is not in the students table.

PostgreSQL

CREATE TABLE students (
  id INT,
  name TEXT
);

CREATE TABLE scores (
  student_id INT,
  score INT
);

INSERT INTO students VALUES
(1, 'Alice'),
(2, 'Bob'),
(3, 'Charlie');

INSERT INTO scores VALUES
(1, 85),
(3, 90),
(4, 75);

SELECT students.id, students.name, scores.score
FROM students
FULL OUTER JOIN scores
ON students.id = scores.student_id
ORDER BY students.id NULLS LAST, scores.student_id NULLS LAST;

Important Notes

FULL OUTER JOIN can return NULLs when there is no matching row in one of the tables.

Ordering results with NULLS LAST or NULLS FIRST helps keep output clear.

Use FULL OUTER JOIN when you want to keep all data from both tables, not just matches.

Summary

FULL OUTER JOIN combines all rows from two tables.

It shows matching rows and also rows without matches from either table.

Unmatched columns show NULL values.

Practice

1. What does a FULL OUTER JOIN do in PostgreSQL?

easy

A. It returns all rows from the right table and matching rows from the left table.

B. It returns only rows that have matching values in both tables.

C. It returns all rows from the left table and matching rows from the right table.

D. It returns all rows from both tables, matching where possible, and NULLs where no match exists.

Solution

1. Step 1: Understand the join types

   INNER JOIN returns only matching rows; LEFT JOIN returns all left table rows plus matches; RIGHT JOIN returns all right table rows plus matches.

2. Step 2: Define FULL OUTER JOIN behavior

   FULL OUTER JOIN returns all rows from both tables, matching where possible, and fills unmatched columns with NULL.

3. Final Answer:

   It returns all rows from both tables, matching where possible, and NULLs where no match exists. -> Option D

4. Quick Check:

   FULL OUTER JOIN = all rows both tables [OK]

Hint: Remember: FULL OUTER JOIN = all rows from both tables [OK]

Common Mistakes:

• Confusing FULL OUTER JOIN with INNER JOIN
• Thinking FULL OUTER JOIN returns only left or right table rows
• Assuming unmatched rows are excluded

2. Which of the following is the correct syntax for a FULL OUTER JOIN in PostgreSQL?

easy

A. SELECT * FROM table1 FULL OUTER JOIN table2 ON table1.id = table2.id;

B. SELECT * FROM table1 JOIN FULL OUTER table2 ON table1.id = table2.id;

C. SELECT * FROM table1 FULL JOIN table2 WHERE table1.id = table2.id;

D. SELECT * FROM table1 OUTER FULL JOIN table2 ON table1.id = table2.id;

Solution

1. Step 1: Recall PostgreSQL FULL OUTER JOIN syntax

   The correct syntax is: SELECT ... FROM table1 FULL OUTER JOIN table2 ON condition;

2. Step 2: Check each option

   The syntax 'SELECT * FROM table1 FULL OUTER JOIN table2 ON table1.id = table2.id;' matches exactly. Others err: 'JOIN FULL OUTER' wrong order; 'FULL JOIN ... WHERE' misuses WHERE for join; 'OUTER FULL JOIN' wrong sequence.

3. Final Answer:

   SELECT * FROM table1 FULL OUTER JOIN table2 ON table1.id = table2.id; -> Option A

4. Quick Check:

   FULL OUTER JOIN syntax = FULL OUTER JOIN ON [OK]

Hint: FULL OUTER JOIN always uses 'FULL OUTER JOIN ... ON' syntax [OK]

Common Mistakes:

• Swapping JOIN and FULL OUTER keywords
• Omitting ON clause
• Using WHERE instead of ON for join condition

3. Given these tables:
Table A:
ID | Name
1 | Alice
2 | Bob
4 | Diana

Table B:
ID | City
2 | Paris
3 | London
4 | Berlin

What is the result of:
SELECT COALESCE(A.ID, B.ID) AS ID, A.Name, B.City FROM A FULL OUTER JOIN B ON A.ID = B.ID ORDER BY ID;

medium

A. [{2, 'Bob', 'Paris'}, {3, NULL, 'London'}, {4, 'Diana', 'Berlin'}]

B. [{1, 'Alice', NULL}, {2, 'Bob', NULL}, {3, NULL, 'London'}, {4, 'Diana', 'Berlin'}]

C. [{1, 'Alice', NULL}, {2, 'Bob', 'Paris'}, {3, NULL, 'London'}, {4, 'Diana', 'Berlin'}]

D. [{1, 'Alice', NULL}, {2, 'Bob', 'Paris'}, {4, 'Diana', 'Berlin'}]

Solution

1. Step 1: Identify matching and unmatched IDs

   Matching IDs: 2 and 4. Unmatched in A: 1. Unmatched in B: 3.

2. Step 2: Construct FULL OUTER JOIN result

   Rows:
   - ID 1: Name 'Alice', City NULL (no match in B)
   - ID 2: Name 'Bob', City 'Paris' (match)
   - ID 3: Name NULL, City 'London' (no match in A)
   - ID 4: Name 'Diana', City 'Berlin' (match)

3. Final Answer:

   [{1, 'Alice', NULL}, {2, 'Bob', 'Paris'}, {3, NULL, 'London'}, {4, 'Diana', 'Berlin'}] -> Option C

4. Quick Check:

   FULL OUTER JOIN includes all rows with NULLs for unmatched [OK]

Hint: Match IDs, include all rows, NULL for missing side [OK]

Common Mistakes:

• Excluding unmatched rows from either table
• Mixing up NULL placement
• Ordering rows incorrectly

4. Consider this query:
SELECT * FROM A FULL OUTER JOIN B ON A.id = B.id WHERE A.name = 'Alice';
Why might this query return fewer rows than expected?

medium

A. Because the WHERE clause filters out rows where A.name is NULL, excluding unmatched rows from B.

B. Because FULL OUTER JOIN only returns matching rows.

C. Because the ON condition is incorrect syntax.

D. Because the query needs GROUP BY to include all rows.

Solution

1. Step 1: Understand FULL OUTER JOIN with WHERE clause

   FULL OUTER JOIN returns all rows, but WHERE filters after join. Filtering on A.name excludes rows where A.name is NULL (unmatched in A).

2. Step 2: Effect of filtering on unmatched rows

   Rows unmatched in A have NULL for A.name, so WHERE A.name = 'Alice' removes them, reducing rows.

3. Final Answer:

   Because the WHERE clause filters out rows where A.name is NULL, excluding unmatched rows from B. -> Option A

4. Quick Check:

   WHERE filters after join, can exclude NULLs [OK]

Hint: Use WHERE carefully; it filters after join, may exclude NULLs [OK]

Common Mistakes:

• Thinking FULL OUTER JOIN ignores WHERE filters
• Assuming ON clause filters rows after join
• Believing GROUP BY affects join row count

5. You have two tables:
Employees(emp_id, name) and Departments(dept_id, emp_id, dept_name).
You want a list of all employees and their departments if any, plus all departments and their employees if any.
Which query correctly uses FULL OUTER JOIN to achieve this?

hard

A. SELECT e.emp_id, e.name, d.dept_name FROM Employees e RIGHT JOIN Departments d ON e.emp_id = d.emp_id;

B. SELECT e.emp_id, e.name, d.dept_name FROM Employees e FULL OUTER JOIN Departments d ON e.emp_id = d.emp_id;

C. SELECT e.emp_id, e.name, d.dept_name FROM Employees e INNER JOIN Departments d ON e.emp_id = d.emp_id;

D. SELECT e.emp_id, e.name, d.dept_name FROM Employees e LEFT JOIN Departments d ON e.emp_id = d.emp_id;

Solution

1. Step 1: Understand the requirement

   We want all employees and their departments if any, plus all departments and their employees if any. This means all rows from both tables.

2. Step 2: Choose the correct join type

   FULL OUTER JOIN returns all rows from both tables, matching where possible. LEFT or RIGHT JOIN only return all rows from one table.

3. Final Answer:

   SELECT e.emp_id, e.name, d.dept_name FROM Employees e FULL OUTER JOIN Departments d ON e.emp_id = d.emp_id; -> Option B

4. Quick Check:

   FULL OUTER JOIN returns all rows both tables [OK]

Hint: Use FULL OUTER JOIN to include all rows from both tables [OK]

Common Mistakes:

• Using LEFT or RIGHT JOIN excludes unmatched rows from one table
• Using INNER JOIN excludes unmatched rows
• Forgetting ON condition