Array aggregation with ARRAY_AGG in PostgreSQL - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to select all user IDs aggregated into an array.

PostgreSQL

SELECT [1](user_id) FROM users;

Drag options to blanks, or click blank then click option'

AARRAY_AGG

BCOUNT

CMAX

DSUM

Attempts:

3 left

💡 Hint

Common Mistakes

Using COUNT instead of ARRAY_AGG returns a number, not an array.

Using SUM or MAX returns a single value, not an array.

The ARRAY_AGG function collects values into an array. Here, it gathers all user_id values.

2fill in blank

medium

Complete the code to aggregate product names into an array grouped by category.

PostgreSQL

SELECT category, [1](product_name) FROM products GROUP BY category;

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AAVG

BCOUNT

CMIN

DARRAY_AGG

Attempts:

3 left

💡 Hint

Common Mistakes

Using COUNT returns the number of products, not their names.

Using AVG or MIN does not work on text fields.

ARRAY_AGG collects all product_name values per category into arrays.

3fill in blank

hard

Fix the error in the code to aggregate emails into an array.

PostgreSQL

SELECT ARRAY_AGG[1] FROM contacts;

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A(DISTINCT email)

B[

C{

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Missing parentheses causes syntax errors.

Using brackets or braces is invalid syntax.

To aggregate unique emails, use ARRAY_AGG(DISTINCT email). The parentheses and DISTINCT keyword are required.

4fill in blank

hard

Complete the code to aggregate distinct tags into an array grouped by post ID.

PostgreSQL

SELECT post_id, ARRAY_AGG[1]tags FROM post_tags GROUP BY post_id;

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A(DISTINCT

B)

C;

D]

Attempts:

3 left

💡 Hint

Common Mistakes

Forgetting to close parentheses causes errors.

Using semicolon or brackets instead of closing parenthesis is invalid.

Use ARRAY_AGG(DISTINCT tags) with parentheses and DISTINCT to get unique tags per post.

5fill in blank

hard

Fill all three blanks to aggregate user names in uppercase into an array grouped by city.

PostgreSQL

SELECT city, ARRAY_AGG([1]([2])) AS users FROM users GROUP BY [3];

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AUPPER

Buser_name

Ccity

DLOWER

Attempts:

3 left

💡 Hint

Common Mistakes

Using LOWER instead of UPPER changes case incorrectly.

Grouping by user_name instead of city changes the grouping.

This query groups users by city and aggregates their names in uppercase using ARRAY_AGG(UPPER(user_name)).

Practice

1. What does the PostgreSQL function ARRAY_AGG do?

easy

A. It counts the number of rows in a table.

B. It collects multiple row values into a single array.

C. It sorts rows in ascending order.

D. It deletes duplicate rows from a table.

Solution

1. Step 1: Understand the purpose of ARRAY_AGG

   ARRAY_AGG is used to gather multiple values from rows into one array value.

2. Step 2: Compare with other options

   Counting rows uses COUNT(), deleting duplicates or sorting rows uses other clauses like DISTINCT or ORDER BY, not ARRAY_AGG.

3. Final Answer:

   It collects multiple row values into a single array. -> Option B

4. Quick Check:

   ARRAY_AGG = collects rows into array [OK]

Hint: ARRAY_AGG groups rows into one array [OK]

Common Mistakes:

• Confusing ARRAY_AGG with COUNT or ORDER BY
• Thinking ARRAY_AGG sorts data by default
• Assuming ARRAY_AGG removes duplicates automatically

2. Which of the following is the correct syntax to aggregate values into an array using ARRAY_AGG in PostgreSQL?

easy

A. SELECT ARRAY_AGG(column_name) FROM table_name;

B. SELECT ARRAY_AGG column_name FROM table_name;

C. SELECT ARRAY_AGG(column_name) table_name;

D. SELECT ARRAY_AGG(column_name) FROM table_name WHERE;

Solution

1. Step 1: Recall correct function call syntax

   ARRAY_AGG requires parentheses around the column name and a FROM clause.

2. Step 2: Check each option

   SELECT ARRAY_AGG(column_name) FROM table_name; uses correct syntax with parentheses and FROM clause; others miss parentheses or have syntax errors.

3. Final Answer:

   SELECT ARRAY_AGG(column_name) FROM table_name; -> Option A

4. Quick Check:

   Correct ARRAY_AGG syntax uses parentheses and FROM [OK]

Hint: Always use parentheses with ARRAY_AGG(column) [OK]

Common Mistakes:

• Omitting parentheses around column_name
• Leaving incomplete WHERE clause
• Missing FROM keyword

3. Given the table students with columns class and name, what is the output of this query?

SELECT class, ARRAY_AGG(name ORDER BY name) FROM students GROUP BY class ORDER BY class;

medium

A. [{class: '1A', array_agg: ['Alice']}, {class: '2B', array_agg: ['Charlie', 'David', 'Bob']}]

B. [{class: '1A', array_agg: ['Bob', 'Alice']}, {class: '2B', array_agg: ['David', 'Charlie']}]

C. [{class: '1A', array_agg: ['Alice', 'Charlie']}, {class: '2B', array_agg: ['Bob', 'David']}]

D. [{class: '1A', array_agg: ['Alice', 'Bob']}, {class: '2B', array_agg: ['Charlie', 'David']}]

Solution

1. Step 1: Understand GROUP BY and ARRAY_AGG with ORDER BY

   The query groups rows by class and collects names into arrays sorted alphabetically.

2. Step 2: Analyze the ordering inside ARRAY_AGG

   Names inside each class array are sorted ascending, so 'Alice' comes before 'Bob' in '1A', and 'Charlie' before 'David' in '2B'.

3. Final Answer:

   [{class: '1A', array_agg: ['Alice', 'Bob']}, {class: '2B', array_agg: ['Charlie', 'David']}] -> Option D

4. Quick Check:

   ARRAY_AGG with ORDER BY sorts array elements [OK]

Hint: ARRAY_AGG(... ORDER BY ...) sorts array elements [OK]

Common Mistakes:

• Ignoring ORDER BY inside ARRAY_AGG
• Mixing names between groups
• Assuming ARRAY_AGG sorts groups, not elements

4. Identify the error in this query:

SELECT class, ARRAY_AGG(name ORDER BY) FROM students GROUP BY class;

medium

A. Missing column name after ORDER BY inside ARRAY_AGG.

B. GROUP BY clause is not allowed with ARRAY_AGG.

C. ARRAY_AGG cannot be used with ORDER BY.

D. Missing FROM keyword before table name.

Solution

1. Step 1: Check syntax of ORDER BY inside ARRAY_AGG

   ORDER BY inside ARRAY_AGG requires a column name to specify sorting order.

2. Step 2: Validate other parts of the query

   GROUP BY is valid with ARRAY_AGG; FROM clause is present; ORDER BY without column is invalid.

3. Final Answer:

   Missing column name after ORDER BY inside ARRAY_AGG. -> Option A

4. Quick Check:

   ORDER BY needs a column name inside ARRAY_AGG [OK]

Hint: ORDER BY inside ARRAY_AGG needs a column name [OK]

Common Mistakes:

• Leaving ORDER BY empty inside ARRAY_AGG
• Thinking GROUP BY disallows ARRAY_AGG
• Forgetting to specify sorting column

5. You have a table orders with columns customer_id and product. You want to create a query that returns each customer_id with an array of unique products they ordered, sorted alphabetically. Which query achieves this?

hard

A. SELECT customer_id, ARRAY_AGG(product ORDER BY product) FROM orders GROUP BY customer_id;

B. SELECT customer_id, ARRAY_AGG(DISTINCT product) FROM orders GROUP BY customer_id ORDER BY product;

C. SELECT customer_id, ARRAY_AGG(DISTINCT product ORDER BY product) FROM orders GROUP BY customer_id;

D. SELECT customer_id, ARRAY_AGG(product) FROM orders ORDER BY customer_id;

Solution

1. Step 1: Use ARRAY_AGG with DISTINCT and ORDER BY

   To get unique products sorted, use ARRAY_AGG(DISTINCT product ORDER BY product).

2. Step 2: Group by customer_id to aggregate per customer

   GROUP BY customer_id ensures aggregation per customer; ORDER BY inside ARRAY_AGG sorts products alphabetically.

3. Final Answer:

   SELECT customer_id, ARRAY_AGG(DISTINCT product ORDER BY product) FROM orders GROUP BY customer_id; -> Option C

4. Quick Check:

   Use DISTINCT inside ARRAY_AGG with ORDER BY for unique sorted arrays [OK]

Hint: Use DISTINCT inside ARRAY_AGG with ORDER BY for unique sorted arrays [OK]

Common Mistakes:

• Omitting DISTINCT causes duplicates in array
• Placing ORDER BY outside ARRAY_AGG affects rows, not array elements
• Not grouping by customer_id