UUID type and generation in PostgreSQL - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a table with a UUID primary key column.

PostgreSQL

CREATE TABLE users (id [1] PRIMARY KEY);

Drag options to blanks, or click blank then click option'

AUUID

BINT

CTEXT

DSERIAL

Attempts:

3 left

💡 Hint

Common Mistakes

Using INT or SERIAL instead of UUID for unique IDs.

The UUID type stores universally unique identifiers, perfect for unique keys.

2fill in blank

medium

Complete the code to generate a random UUID value.

PostgreSQL

SELECT [1]();

Drag options to blanks, or click blank then click option'

Arandom_uuid

Buuid_generate_v4

Cuuid_generate_v1

Dgen_random_uuid

Attempts:

3 left

💡 Hint

Common Mistakes

Using uuid_generate_v1() which generates time-based UUIDs.

gen_random_uuid() generates a random UUID (version 4) in PostgreSQL.

3fill in blank

hard

Fix the error in the code to insert a new row with a generated UUID.

PostgreSQL

INSERT INTO orders (order_id) VALUES ([1]());

Drag options to blanks, or click blank then click option'

Agen_random_uuid

Buuid_generate_v4

Cuuid_generate_v2

Drandom

Attempts:

3 left

💡 Hint

Common Mistakes

Using non-existent functions like uuid_generate_v2() or random().

gen_random_uuid() is the correct function to generate a random UUID for insertion.

4fill in blank

hard

Fill both blanks to create a table with a UUID primary key that defaults to a generated UUID.

PostgreSQL

CREATE TABLE sessions (session_id [1] PRIMARY KEY DEFAULT [2]());

Drag options to blanks, or click blank then click option'

AUUID

BTEXT

Cgen_random_uuid

Duuid_generate_v4

Attempts:

3 left

💡 Hint

Common Mistakes

Using TEXT type or wrong default functions for UUID columns.

The session_id column should be of type UUID and default to gen_random_uuid() to auto-generate unique IDs.

5fill in blank

hard

Fill all three blanks to select UUIDs from a table where the UUID is not null and order by UUID.

PostgreSQL

SELECT [1] FROM devices WHERE [2] IS NOT NULL ORDER BY [3];

Drag options to blanks, or click blank then click option'

Adevice_id

Buuid

Did

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing different column names or using columns that don't exist.

We select the device_id column, filter where it is not null, and order by the same column.

Practice

1. What is the main purpose of using a UUID type in PostgreSQL?

easy

A. To store unique identifiers that avoid duplicates across tables or systems

B. To store large text data efficiently

C. To perform mathematical calculations faster

D. To create indexes automatically on a table

Solution

1. Step 1: Understand UUID purpose

   UUID stands for Universally Unique Identifier, designed to be unique across space and time.

2. Step 2: Identify its use in PostgreSQL

   PostgreSQL uses UUID to store unique IDs that avoid duplicates, especially in distributed systems.

3. Final Answer:

   To store unique identifiers that avoid duplicates across tables or systems -> Option A

4. Quick Check:

   UUID = Unique ID storage [OK]

Hint: UUIDs are for unique IDs, not for text or math [OK]

Common Mistakes:

• Confusing UUID with text or numeric types
• Thinking UUID speeds up math operations
• Assuming UUID auto-creates indexes

2. Which of the following is the correct way to generate a random UUID in PostgreSQL?

easy

A. SELECT uuid_generate_v4();

B. SELECT random_uuid();

C. SELECT gen_random_uuid();

D. SELECT create_uuid();

Solution

1. Step 1: Recall PostgreSQL UUID functions

   PostgreSQL's pgcrypto extension provides gen_random_uuid() to generate random UUIDs.

2. Step 2: Check function names

   uuid_generate_v4() is from another extension (uuid-ossp), not default. The others are invalid.

3. Final Answer:

   SELECT gen_random_uuid(); -> Option C

4. Quick Check:

   Random UUID function = gen_random_uuid() [OK]

Hint: Use gen_random_uuid() with pgcrypto extension [OK]

Common Mistakes:

• Using uuid_generate_v4() without enabling uuid-ossp
• Typing random_uuid() which does not exist
• Confusing function names

3. Given the table creation and insert statements below, what will be the output of the SELECT query?

CREATE EXTENSION IF NOT EXISTS pgcrypto;
CREATE TABLE users (id UUID PRIMARY KEY DEFAULT gen_random_uuid(), name TEXT);
INSERT INTO users (name) VALUES ('Alice'), ('Bob');
SELECT id, name FROM users ORDER BY name;

medium

A. Two rows with NULL ids for Alice and Bob

B. Two rows with unique UUIDs for Alice and Bob, ordered by name

C. Syntax error because gen_random_uuid() is not allowed in DEFAULT

D. One row only because UUID duplicates cause conflict

Solution

1. Step 1: Understand table and insert behavior

   The table uses gen_random_uuid() as default for id. Inserting names without specifying id generates unique UUIDs automatically.

2. Step 2: Analyze SELECT output

   The SELECT query returns all rows ordered by name, showing unique UUIDs for Alice and Bob.

3. Final Answer:

   Two rows with unique UUIDs for Alice and Bob, ordered by name -> Option B

4. Quick Check:

   Default UUID generates unique IDs [OK]

Hint: DEFAULT gen_random_uuid() auto-fills unique IDs [OK]

Common Mistakes:

• Expecting NULL ids when default is set
• Thinking gen_random_uuid() causes syntax error
• Assuming UUID duplicates block inserts

4. You run the following commands but get an error: ERROR: function gen_random_uuid() does not exist. What is the most likely fix?

SELECT gen_random_uuid();

medium

A. Change the query to SELECT random_uuid();

B. Use uuid_generate_v4() instead without any extension

C. Restart PostgreSQL server to refresh functions

D. Enable the pgcrypto extension using CREATE EXTENSION pgcrypto;

Solution

1. Step 1: Identify cause of missing function

   The error means gen_random_uuid() is not available because the pgcrypto extension is not enabled.

2. Step 2: Apply correct fix

   Enabling pgcrypto with CREATE EXTENSION pgcrypto; adds the function.

3. Final Answer:

   Enable the pgcrypto extension using CREATE EXTENSION pgcrypto; -> Option D

4. Quick Check:

   Missing function = enable pgcrypto [OK]

Hint: Enable pgcrypto extension to use gen_random_uuid() [OK]

Common Mistakes:

• Trying uuid_generate_v4() without enabling uuid-ossp
• Restarting server unnecessarily
• Using random_uuid() which does not exist

5. You want to create a table that stores user sessions with a UUID primary key generated automatically, but also want to insert a specific UUID sometimes. Which table definition and insert statement is correct?

CREATE EXTENSION IF NOT EXISTS pgcrypto;
CREATE TABLE sessions (
  session_id UUID PRIMARY KEY DEFAULT gen_random_uuid(),
  user_id INT
);

-- Insert with automatic UUID
INSERT INTO sessions (user_id) VALUES (101);

-- Insert with specific UUID
INSERT INTO sessions (session_id, user_id) VALUES ('550e8400-e29b-41d4-a716-446655440000', 102);

hard

A. This setup works correctly, allowing both automatic and manual UUID insertion

B. You cannot insert a specific UUID if DEFAULT is set for the column

C. You must disable the default to insert specific UUIDs

D. The UUID must be generated outside PostgreSQL and inserted as text

Solution

1. Step 1: Understand DEFAULT with manual insert

   Setting DEFAULT to gen_random_uuid() means if no value is given, PostgreSQL generates one automatically.

2. Step 2: Check manual UUID insertion

   When you specify session_id explicitly, PostgreSQL uses that value instead of the default.

3. Step 3: Confirm correctness

   This allows both automatic UUID generation and manual UUID insertion in the same table.

4. Final Answer:

   This setup works correctly, allowing both automatic and manual UUID insertion -> Option A

5. Quick Check:

   DEFAULT allows manual override [OK]

Hint: DEFAULT UUID generates only if no value given [OK]

Common Mistakes:

• Thinking DEFAULT blocks manual inserts
• Trying to disable default for manual UUIDs
• Assuming UUID must be generated outside PostgreSQL