SIMILAR TO for regex-lite matching in PostgreSQL - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to select names that start with 'A' using SIMILAR TO.

PostgreSQL

SELECT name FROM employees WHERE name [1] 'A%';

Drag options to blanks, or click blank then click option'

ASIMILAR TO

BLIKE

CILIKE

D=

Attempts:

3 left

💡 Hint

Common Mistakes

Using LIKE instead of SIMILAR TO for regex-like matching.

Using = which checks exact equality.

The SIMILAR TO operator allows pattern matching using a simplified regex-like syntax. Here, it matches names starting with 'A'.

2fill in blank

medium

Complete the code to find emails ending with '.com' using SIMILAR TO.

PostgreSQL

SELECT email FROM users WHERE email [1] '%\.com';

Drag options to blanks, or click blank then click option'

ASIMILAR TO

BLIKE

CILIKE

DNOT LIKE

Attempts:

3 left

💡 Hint

Common Mistakes

Not escaping the dot '.' causing wrong matches.

Using LIKE which does not support regex escapes.

SIMILAR TO supports regex-like patterns. The pattern '%\.com' matches strings ending with '.com'.

3fill in blank

hard

Fix the error in the query to match phone numbers with exactly 10 digits using SIMILAR TO.

PostgreSQL

SELECT phone FROM contacts WHERE phone [1] '[0-9]{10}';

Drag options to blanks, or click blank then click option'

ALIKE

BSIMILAR TO

C=

DILIKE

Attempts:

3 left

💡 Hint

Common Mistakes

Using LIKE which does not support regex quantifiers.

Using = which checks exact string equality.

SIMILAR TO supports regex quantifiers like {10}. Using SIMILAR TO matches exactly 10 digits.

4fill in blank

hard

Fill both blanks to select usernames starting with a letter and followed by digits using SIMILAR TO.

PostgreSQL

SELECT username FROM accounts WHERE username [1] '[2][0-9]+';

Drag options to blanks, or click blank then click option'

ASIMILAR TO

BLIKE

C[A-Za-z]

D[0-9]

Attempts:

3 left

💡 Hint

Common Mistakes

Using LIKE instead of SIMILAR TO.

Using wrong character class for the first character.

The operator SIMILAR TO is used for regex-like matching. The pattern [A-Za-z][0-9]+ matches usernames starting with a letter followed by one or more digits.

5fill in blank

hard

Fill all three blanks to select product codes that start with 'P', followed by 3 digits, and end with a letter using SIMILAR TO.

PostgreSQL

SELECT product_code FROM inventory WHERE product_code [1] '[2][3][A-Za-z]';

Drag options to blanks, or click blank then click option'

ASIMILAR TO

BP

C[0-9]{3}

DLIKE

Attempts:

3 left

💡 Hint

Common Mistakes

Using LIKE instead of SIMILAR TO.

Not using quantifier {3} for digits.

Missing the starting 'P' in the pattern.

Use SIMILAR TO for regex-like matching. The pattern P[0-9]{3}[A-Za-z] matches codes starting with 'P', then exactly 3 digits, and ending with a letter.

Practice

1. Which of the following best describes the SIMILAR TO operator in PostgreSQL?

easy

A. It matches strings using simple patterns with % and _ wildcards and some regex features.

B. It performs exact string matching without any pattern support.

C. It is used to compare numeric values with tolerance.

D. It matches strings only using full regular expressions.

Solution

1. Step 1: Understand SIMILAR TO purpose

   The SIMILAR TO operator matches strings using patterns that include % (any sequence) and _ (any single character), plus some regex-like features such as + and |.

2. Step 2: Compare options

   It matches strings using simple patterns with % and _ wildcards and some regex features. correctly describes this behavior. Options B, C, and D describe other unrelated behaviors.

3. Final Answer:

   It matches strings using simple patterns with % and _ wildcards and some regex features. -> Option A

4. Quick Check:

   SIMILAR TO = simple pattern matching [OK]

Hint: SIMILAR TO uses % and _ plus simple regex features [OK]

Common Mistakes:

• Confusing SIMILAR TO with full regex matching (~ operator)
• Thinking SIMILAR TO matches exact strings only
• Assuming SIMILAR TO works like numeric comparison

2. Which of the following is the correct syntax to check if column name matches a pattern starting with 'A' followed by any characters using SIMILAR TO?

easy

A. name SIMILAR TO 'A_'

B. name SIMILAR TO '%A'

C. name SIMILAR TO '_A%'

D. name SIMILAR TO 'A%'

Solution

1. Step 1: Understand pattern meaning

   The pattern 'A%' means the string starts with 'A' followed by any sequence of characters.

2. Step 2: Match pattern to options

   name SIMILAR TO 'A%' uses 'A%' which matches strings starting with 'A'. name SIMILAR TO '%A' matches strings ending with 'A'. name SIMILAR TO '_A%' requires second character 'A'. name SIMILAR TO 'A_' matches strings starting with 'A' and exactly one more character.

3. Final Answer:

   name SIMILAR TO 'A%' -> Option D

4. Quick Check:

   Start with 'A' = 'A%' [OK]

Hint: Use % after 'A' to match any characters after 'A' [OK]

Common Mistakes:

• Using % before 'A' to match start
• Confusing _ with %
• Using wrong pattern length

3. Given the table users(name TEXT) with rows: 'Anna', 'Anny', 'Andy', 'Any', which query returns only names starting with 'An' and ending with 'y' using SIMILAR TO?

medium

A. SELECT name FROM users WHERE name SIMILAR TO 'An%y';

B. SELECT name FROM users WHERE name SIMILAR TO 'An_y';

C. SELECT name FROM users WHERE name SIMILAR TO 'An_y%';

D. SELECT name FROM users WHERE name SIMILAR TO 'An_y_';

Solution

1. Step 1: Analyze pattern requirements

   We want names starting with 'An' and ending with 'y'. The middle can be any number of characters (including zero).

2. Step 2: Check each pattern

   SELECT name FROM users WHERE name SIMILAR TO 'An_y'; 'An_y' matches exactly 4 characters: 'An' + any single char + 'y' (matches 'Anny', 'Andy'; not 'Any'). SELECT name FROM users WHERE name SIMILAR TO 'An%y'; 'An%y' matches starting 'An', any characters in middle, ending with 'y' (matches 'Anny', 'Andy', 'Any'). SELECT name FROM users WHERE name SIMILAR TO 'An_y%'; 'An_y%' requires 4 characters minimum ('An' + single + 'y' + any after), matches 'Anny', 'Andy' (not 'Any'). SELECT name FROM users WHERE name SIMILAR TO 'An_y_'; 'An_y_' requires exactly 5 characters, no match.

3. Final Answer:

   SELECT name FROM users WHERE name SIMILAR TO 'An%y'; -> Option A

4. Quick Check:

   Start 'An', end 'y' = 'An%y' [OK]

Hint: Use % to match any length between start and end [OK]

Common Mistakes:

• Using _ instead of % for variable length
• Forgetting to include ending 'y' in pattern
• Assuming _ matches multiple characters

4. Consider this query: SELECT * FROM products WHERE code SIMILAR TO '[A-Z]+[0-9]'. It returns no rows even though some codes look like 'AB12'. What is the likely problem?

medium

A. The pattern matches only codes with exactly two characters.

B. SIMILAR TO does not support character classes like [A-Z] and [0-9].

C. The pattern should use % and _ instead of + for repetition.

D. The query syntax is invalid and causes an error.

Solution

1. Step 1: Understand SIMILAR TO pattern syntax

   SIMILAR TO supports some regex features but uses % for any sequence and _ for single character. The + operator is supported but character classes like [A-Z] are not fully supported as in full regex.

2. Step 2: Identify correct pattern usage

   Using [A-Z]+ is not valid in SIMILAR TO. Instead, use something like '(A|B|C|...)+'. Also, to match digits, use '[0-9]' carefully or replace with ranges or alternatives. The pattern should be rewritten using % and _ or explicit alternatives.

3. Final Answer:

   The pattern should use % and _ instead of + for repetition. -> Option C

4. Quick Check:

   SIMILAR TO needs %/_ for repetition, not + with classes [OK]

Hint: Use % and _ wildcards, not full regex classes [OK]

Common Mistakes:

• Assuming SIMILAR TO supports full regex syntax
• Using + without proper grouping
• Expecting character classes to work like full regex

5. You want to find all usernames in table users that start with either 'admin' or 'user' followed by exactly 3 digits. Which SIMILAR TO pattern correctly matches this?

hard

A. username SIMILAR TO '(admin|user)[0-9]{3}'

B. username SIMILAR TO '(admin|user)[0-9][0-9][0-9]'

C. username SIMILAR TO '(admin|user)%[0-9][0-9][0-9]'

D. username SIMILAR TO '(admin|user)_[0-9]{3}'

Solution

1. Step 1: Understand SIMILAR TO limitations

   SIMILAR TO supports alternation (|) and grouping with parentheses. However, it does not support {n} repetition syntax like full regex.

2. Step 2: Match exactly 3 digits

   To match exactly 3 digits, write [0-9][0-9][0-9] explicitly instead of [0-9]{3}.

3. Step 3: Check options

   username SIMILAR TO '(admin|user)[0-9]{3}' uses {3} which is invalid in SIMILAR TO. username SIMILAR TO '(admin|user)[0-9][0-9][0-9]' uses explicit three digit classes, correct. username SIMILAR TO '(admin|user)%[0-9][0-9][0-9]' uses % which matches any sequence, so it allows extra characters between prefix and digits, incorrect. username SIMILAR TO '(admin|user)_[0-9]{3}' uses _ which matches one character, but {3} is invalid.

4. Final Answer:

   username SIMILAR TO '(admin|user)[0-9][0-9][0-9]' -> Option B

5. Quick Check:

   Use explicit digit repeats, no {n} in SIMILAR TO [OK]

Hint: Write repeated patterns explicitly; no {n} in SIMILAR TO [OK]

Common Mistakes:

• Using {n} repetition syntax
• Using % wildcard to match exact length
• Confusing _ with digit matching