Prepared statements and why they matter in PHP - Mini Project: Build & Apply

Prepared statements and why they matter

📖 Scenario: You are building a simple PHP script to safely insert user data into a database. This is important to prevent security problems like SQL injection, which can happen if user input is added directly to SQL commands.

🎯 Goal: Learn how to use prepared statements in PHP to safely insert data into a MySQL database.

📋 What You'll Learn

Create a MySQLi connection variable called $conn with the given parameters

Create variables $name and $email with exact values

Prepare an SQL insert statement using prepare() on $conn

Bind parameters using bind_param() with correct types and variables

Execute the prepared statement using execute()

Print "User added successfully" if insertion works

💡 Why This Matters

🌍 Real World

Prepared statements are used in real websites and apps to safely add or get data from databases without risking security.

💼 Career

Knowing prepared statements is essential for backend developers, database administrators, and anyone working with data storage to write secure and reliable code.

1

Create database connection and user data variables

Create a MySQLi connection variable called $conn connecting to host localhost, username root, password password123, and database testdb. Then create two variables: $name with value "Alice" and $email with value "[e-mail]".

PHP

<?php
// Your code here

Hint

Use new mysqli(host, user, password, database) to connect.

2

Prepare the SQL insert statement

Using the $conn variable, create a prepared statement variable called $stmt by calling prepare() with the SQL string: "INSERT INTO users (name, email) VALUES (?, ?)".

PHP

<?php
$conn = new mysqli("localhost", "root", "password123", "testdb");
$name = "Alice";
$email = "[e-mail]";
// Your code here

Hint

Use question marks ? as placeholders for values.

3

Bind parameters and execute the statement

Use bind_param() on $stmt to bind the variables $name and $email with types "ss". Then call execute() on $stmt.

PHP

prepare("INSERT INTO users (name, email) VALUES (?, ?)");
// Your code here

Hint

Use bind_param("ss", $name, $email) to bind two string parameters.

4

Print success message

After executing the statement, print the exact text "User added successfully".

PHP

prepare("INSERT INTO users (name, email) VALUES (?, ?)");
$stmt->bind_param("ss", $name, $email);
$stmt->execute();
// Your code here

Hint

Use print("User added successfully") to show the message.

Practice

1. What is the main reason to use prepared statements in PHP when working with databases?

easy

A. To protect the database from SQL injection attacks

B. To make the code run faster by skipping queries

C. To store data permanently in variables

D. To automatically create database tables

Solution

1. Step 1: Understand the purpose of prepared statements

   Prepared statements separate SQL code from user data, preventing malicious input from changing the query.

2. Step 2: Identify the security benefit

   This separation protects against SQL injection, a common hacking method.

3. Final Answer:

   To protect the database from SQL injection attacks -> Option A

4. Quick Check:

   Security = Protect from SQL injection [OK]

Hint: Prepared statements stop hackers from changing your queries [OK]

Common Mistakes:

• Thinking prepared statements speed up queries significantly
• Confusing prepared statements with data storage
• Believing prepared statements create tables automatically

2. Which of the following is the correct syntax to prepare a statement using PDO in PHP?

easy

A. $stmt = $pdo->prepare('SELECT * FROM users WHERE id = ?');

B. $stmt = $pdo->query('SELECT * FROM users WHERE id = ?');

C. $stmt = $pdo->execute('SELECT * FROM users WHERE id = ?');

D. $stmt = $pdo->fetch('SELECT * FROM users WHERE id = ?');

Solution

1. Step 1: Recall PDO method for preparing statements

   The correct method to prepare a statement is prepare(), which sets up the SQL with placeholders.

2. Step 2: Check the options for correct method usage

   Only $stmt = $pdo->prepare('SELECT * FROM users WHERE id = ?'); uses prepare() correctly with a SQL string containing a placeholder.

3. Final Answer:

   $stmt = $pdo->prepare('SELECT * FROM users WHERE id = ?'); -> Option A

4. Quick Check:

   PDO prepare() method = $stmt = $pdo->prepare('SELECT * FROM users WHERE id = ?'); [OK]

Hint: Use prepare() to set up SQL with placeholders [OK]

Common Mistakes:

• Using query() instead of prepare() for statements with placeholders
• Trying to execute SQL directly with execute() without preparing
• Confusing fetch() with prepare()

3. What will be the output of the following PHP code snippet?

$pdo = new PDO('sqlite::memory:');
$pdo->exec('CREATE TABLE users (id INTEGER, name TEXT)');
$stmt = $pdo->prepare('INSERT INTO users (id, name) VALUES (?, ?)');
$stmt->execute([1, 'Alice']);
$stmt->execute([2, 'Bob']);
$stmt = $pdo->prepare('SELECT name FROM users WHERE id = ?');
$stmt->execute([2]);
echo $stmt->fetchColumn();

medium

A. 1

B. Alice

C. Bob

D. Error

Solution

1. Step 1: Insert two users into the table

   The code inserts two rows: id=1 with name 'Alice' and id=2 with name 'Bob'.

2. Step 2: Select the name where id = 2

   The prepared statement selects the name for id=2, which is 'Bob'.

3. Final Answer:

   Bob -> Option C

4. Quick Check:

   Selected name for id=2 = Bob [OK]

Hint: Check which id is queried to find the correct name [OK]

Common Mistakes:

• Confusing the order of inserted rows
• Expecting the first inserted name instead of the queried one
• Assuming an error due to missing database file

4. Identify the error in the following PHP code using prepared statements:

$stmt = $pdo->prepare('SELECT * FROM users WHERE email = :email');
$stmt->execute('[e-mail]');
$result = $stmt->fetchAll();

medium

A. The SQL query is missing a WHERE clause

B. The prepare() method is missing a placeholder

C. fetchAll() cannot be used after execute()

D. The execute() method should receive an array, not a string

Solution

1. Step 1: Check the execute() method argument

   When using named placeholders like ':email', execute() expects an associative array with keys matching placeholders.

2. Step 2: Identify the incorrect argument type

   The code passes a string directly instead of an array like ['email' => '[e-mail]'].

3. Final Answer:

   The execute() method should receive an array, not a string -> Option D

4. Quick Check:

   execute() needs array for named placeholders [OK]

Hint: Pass an array to execute() when using named placeholders [OK]

Common Mistakes:

• Passing a string instead of an array to execute()
• Forgetting to match placeholder names in the array keys
• Thinking fetchAll() cannot follow execute()

5. You want to insert multiple user records safely using prepared statements in PHP. Which approach below correctly uses prepared statements to insert two users with ids and names?

hard

A. $stmt = $pdo->prepare('INSERT INTO users (id, name) VALUES (?, ?)');
$stmt->execute(1, 'Alice');
$stmt->execute(2, 'Bob');

B. $stmt = $pdo->prepare('INSERT INTO users (id, name) VALUES (:id, :name)');
$stmt->execute(['id' => 1, 'name' => 'Alice']);
$stmt->execute(['id' => 2, 'name' => 'Bob']);

C. $pdo->exec("INSERT INTO users (id, name) VALUES (1, 'Alice'), (2, 'Bob')");

D. $stmt = $pdo->prepare('INSERT INTO users (id, name) VALUES (:id, :name)');
$stmt->execute(['id' => 1, 'name' => 'Alice', 'id' => 2, 'name' => 'Bob']);

Solution

1. Step 1: Understand how to use named placeholders for multiple inserts

   Using named placeholders (:id, :name) allows binding values clearly for each execute call.

2. Step 2: Check each option for correct usage

   Only $stmt = $pdo->prepare('INSERT INTO users (id, name) VALUES (:id, :name)'); $stmt->execute(['id' => 1, 'name' => 'Alice']); $stmt->execute(['id' => 2, 'name' => 'Bob']); correctly prepares once and executes twice with separate associative arrays for each user.

3. Step 3: Identify errors in other options

   $stmt = $pdo->prepare('INSERT INTO users (id, name) VALUES (?, ?)'); $stmt->execute(1, 'Alice'); $stmt->execute(2, 'Bob'); incorrectly passes parameters directly to execute() without an array; $pdo->exec("INSERT INTO users (id, name) VALUES (1, 'Alice'), (2, 'Bob')"); uses exec() without preparing; $stmt = $pdo->prepare('INSERT INTO users (id, name) VALUES (:id, :name)'); $stmt->execute(['id' => 1, 'name' => 'Alice', 'id' => 2, 'name' => 'Bob']); tries to pass multiple users in one execute call incorrectly.

4. Final Answer:

   $stmt = $pdo->prepare('INSERT INTO users (id, name) VALUES (:id, :name)'); $stmt->execute(['id' => 1, 'name' => 'Alice']); $stmt->execute(['id' => 2, 'name' => 'Bob']); -> Option B

5. Quick Check:

   Named placeholders + separate execute calls = $stmt = $pdo->prepare('INSERT INTO users (id, name) VALUES (:id, :name)'); $stmt->execute(['id' => 1, 'name' => 'Alice']); $stmt->execute(['id' => 2, 'name' => 'Bob']); [OK]

Hint: Use named placeholders and separate execute() calls per record [OK]

Common Mistakes:

• Passing multiple records in one execute call incorrectly
• Not using prepared statements and risking SQL injection
• Passing parameters to execute() without an array for positional placeholders