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PHPprogramming~10 mins

Named arguments in PHP - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to call the function using a named argument for name.

PHP
<?php
function greet(string $name) {
    echo "Hello, $[1]!";
}
greet(name: "Alice");
?>
Drag options to blanks, or click blank then click option'
AAlice
Bgreet
Cname
Decho
Attempts:
3 left
💡 Hint
Common Mistakes
Using the function name instead of the parameter name.
Using the argument value instead of the parameter name.
2fill in blank
medium

Complete the function call using a named argument for age.

PHP
<?php
function showAge(int $age) {
    echo "Age: $[1]";
}
showAge(age: 30);
?>
Drag options to blanks, or click blank then click option'
AshowAge
Bage
C30
Dint
Attempts:
3 left
💡 Hint
Common Mistakes
Using the function name instead of the parameter name.
Using the argument value instead of the parameter name.
3fill in blank
hard

Fix the error by completing the function call with the correct named argument for city.

PHP
<?php
function printCity(string $city) {
    echo "City: $[1]";
}
printCity(city: "Paris");
?>
Drag options to blanks, or click blank then click option'
Astring
BprintCity
CParis
Dcity
Attempts:
3 left
💡 Hint
Common Mistakes
Using the function name instead of the parameter name.
Using the argument value instead of the parameter name.
4fill in blank
hard

Fill both blanks to call the function with named arguments for firstName and lastName.

PHP
<?php
function fullName(string $firstName, string $lastName) {
    echo "Name: $[1] $[2]";
}
fullName([1]: "John", [2]: "Doe");
?>
Drag options to blanks, or click blank then click option'
AfirstName
BlastName
CJohn
DDoe
Attempts:
3 left
💡 Hint
Common Mistakes
Swapping parameter names.
Using argument values as parameter names.
5fill in blank
hard

Fill all three blanks to call the function with named arguments for title, author, and year.

PHP
<?php
function bookInfo(string $title, string $author, int $year) {
    echo "Book: $[1], Author: $[2], Year: $[3]";
}
bookInfo([1]: "1984", [2]: "Orwell", [3]: 1949);
?>
Drag options to blanks, or click blank then click option'
Atitle
Bauthor
Cyear
Dbook
Attempts:
3 left
💡 Hint
Common Mistakes
Using incorrect parameter names.
Mixing up the order of named arguments.

Practice

(1/5)
1.

What is the main benefit of using named arguments in PHP functions?

easy
A. Named arguments make functions run faster.
B. You must always provide all arguments in order.
C. You can specify arguments by name and change their order.
D. They allow you to define new functions inside existing ones.

Solution

  1. Step 1: Understand named arguments concept

    Named arguments let you specify function parameters by their names instead of position.
  2. Step 2: Identify the benefit

    This allows changing the order of arguments and skipping optional ones, improving readability.
  3. Final Answer:

    You can specify arguments by name and change their order. -> Option C
  4. Quick Check:

    Named arguments = specify by name and reorder [OK]
Hint: Named arguments let you reorder parameters by name [OK]
Common Mistakes:
  • Thinking named arguments speed up execution
  • Believing all arguments must be given in order
  • Confusing named arguments with function definitions
2.

Which of the following is the correct syntax to call a function greet with named arguments name and age?

function greet($name, $age) { return "Hello $name, you are $age."; }
easy
A. greet("Alice", age: 30);
B. greet(name = "Alice", age = 30);
C. greet(age => 30, name => "Alice");
D. greet(name: "Alice", age: 30);

Solution

  1. Step 1: Recall named argument syntax in PHP

    Named arguments use the syntax paramName: value when calling functions.
  2. Step 2: Check each option

    greet(name: "Alice", age: 30); uses name: "Alice" and age: 30, which is correct syntax.
  3. Final Answer:

    greet(name: "Alice", age: 30); -> Option D
  4. Quick Check:

    Named argument syntax = paramName: value [OK]
Hint: Use colon : for named arguments in calls [OK]
Common Mistakes:
  • Using => instead of : for named arguments
  • Using = instead of : in calls
  • Mixing positional and named arguments incorrectly
3.

What will be the output of the following PHP code?

function describe($color, $shape) {
    return "A $color $shape.";
}
echo describe(shape: "circle", color: "red");
medium
A. A red circle.
B. A red.
C. Syntax error.
D. A circle red.

Solution

  1. Step 1: Understand named argument order

    Named arguments allow changing the order of parameters when calling the function.
  2. Step 2: Substitute values in function

    Here, shape is "circle" and color is "red". The return string is "A $color $shape.", so it becomes "A red circle.".
  3. Final Answer:

    A red circle. -> Option A
  4. Quick Check:

    Named arguments reorder parameters = "A red circle." [OK]
Hint: Named arguments reorder parameters without error [OK]
Common Mistakes:
  • Assuming order must match function definition
  • Expecting syntax error from reordered named arguments
  • Mixing up parameter names and values
4.

Identify the error in the following PHP code using named arguments:

function multiply($x, $y) {
    return $x * $y;
}
echo multiply(y: 5, 3);
medium
A. Function multiply is undefined.
B. Positional argument after named argument causes error.
C. Missing colon in named argument syntax.
D. No error; code runs fine.

Solution

  1. Step 1: Check argument order rules

    In PHP, positional arguments must come before named arguments when calling a function.
  2. Step 2: Analyze the call

    The call uses a named argument y: 5 first, then a positional argument 3, which is invalid syntax.
  3. Final Answer:

    Positional argument after named argument causes error. -> Option B
  4. Quick Check:

    Positional args must precede named args [OK]
Hint: Positional args must come before named args [OK]
Common Mistakes:
  • Placing positional arguments after named arguments
  • Forgetting colon in named argument
  • Assuming named arguments can be mixed in any order
5.

Given the function below, which call correctly uses named arguments to skip the optional country parameter and specify city only?

function locationInfo(string $city, string $country = "USA") {
    return "$city, $country";
}
hard
A. locationInfo(city: "Boston");
B. locationInfo("Boston", country: "Canada");
C. locationInfo(city: "Boston", country: "Canada");
D. locationInfo(country: "Canada", city: "Boston");

Solution

  1. Step 1: Understand optional parameters and named arguments

    The country parameter has a default value, so it can be skipped.
  2. Step 2: Identify call that skips country and sets city

    locationInfo(city: "Boston"); calls locationInfo(city: "Boston"), skipping country and using default "USA".
  3. Final Answer:

    locationInfo(city: "Boston"); -> Option A
  4. Quick Check:

    Skip optional params by omitting them in named args [OK]
Hint: Skip optional params by not naming them [OK]
Common Mistakes:
  • Trying to skip required parameters
  • Providing positional argument after named argument
  • Specifying optional parameter unnecessarily
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