Declare strict_types directive in PHP - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to enable strict types in PHP.

PHP

<?php
[1]

function add(int $a, int $b): int {
    return $a + $b;
}

Drag options to blanks, or click blank then click option'

Astrict_types=1;

Bdeclare(strict_types=0);

Cenable_strict_types();

Ddeclare(strict_types=1);

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'strict_types=1;' without 'declare()' function.

Setting strict_types to 0 instead of 1.

Calling a function like 'enable_strict_types()' which does not exist.

The declare(strict_types=1); directive enables strict type checking in PHP.

2fill in blank

medium

Complete the code to correctly declare strict types at the top of the PHP file.

PHP

<?php
[1]

// Your code here

Drag options to blanks, or click blank then click option'

Adeclare(strict_types=1);

Bdeclare(strict_types=0);

Cdeclare(strict=1);

Ddeclare(strict_types);

Attempts:

3 left

💡 Hint

Common Mistakes

Omitting the parentheses.

Using 'strict=1' instead of 'strict_types=1'.

Leaving out the value assignment.

The correct syntax to enable strict types is declare(strict_types=1);.

3fill in blank

hard

Fix the error in the strict types declaration.

PHP

<?php
[1]

function multiply(int $x, int $y): int {
    return $x * $y;
}

Drag options to blanks, or click blank then click option'

Adeclare(strict_types=);

Bdeclare(strict_types=1);

Cdeclare(strict_types=2);

Ddeclare(strict_types=0);

Attempts:

3 left

💡 Hint

Common Mistakes

Leaving the value empty.

Using values other than 0 or 1.

Using 0 which disables strict typing.

The strict_types directive must be set to 1 to enable strict typing. Other values or missing values cause errors.

4fill in blank

hard

Fill both blanks to correctly declare strict types and define a function with strict typing.

PHP

<?php
[1]

function divide(int $a, int $b): float {
    return $a [2] $b;
}

Drag options to blanks, or click blank then click option'

Adeclare(strict_types=1);

B+

C/

D*

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+' or '*' instead of '/' for division.

Omitting the strict types declaration.

Using incorrect syntax for declare.

Strict types are declared with declare(strict_types=1);. The division operator is /.

5fill in blank

hard

Fill all three blanks to declare strict types, define a function, and return the sum of two integers.

PHP

<?php
[1]

function sum([2] $x, [3] $y): int {
    return $x + $y;
}

Drag options to blanks, or click blank then click option'

Adeclare(strict_types=1);

Bint

Cfloat

Dstring

Attempts:

3 left

💡 Hint

Common Mistakes

Using float or string types for parameters when return type is int.

Omitting strict types declaration.

Incorrect syntax in declare statement.

Strict types are declared with declare(strict_types=1);. The function parameters are typed as int to match the return type.