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PHPprogramming~5 mins

Compact and extract functions in PHP - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What does the compact() function do in PHP?
The compact() function creates an array from variables and their values. You give it variable names as strings, and it returns an associative array where keys are the variable names and values are the variable values.
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beginner
What is the purpose of the extract() function in PHP?
The extract() function imports variables into the current symbol table from an associative array. It creates variables named after the array keys and assigns them the corresponding values.
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intermediate
How do compact() and extract() relate to each other?
compact() turns variables into an array, while extract() turns an array back into variables. They are like opposites and can be used to pass variables around easily.
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intermediate
What happens if you use extract() with an array that has keys matching existing variables?
By default, extract() will overwrite existing variables with the same name. You can control this behavior with flags like EXTR_SKIP to avoid overwriting.
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beginner
Show a simple example of using compact() and extract() together.
Example:
$name = "Alice";
$age = 30;
$data = compact('name', 'age');
// $data is ['name' => 'Alice', 'age' => 30]
extract($data);
// Now $name and $age variables exist again with original values
Click to reveal answer
What does compact('x', 'y') return if $x = 5 and $y = 10?
AVariables named 'x' and 'y' with values 5 and 10
BAn array [5, 10]
CAn array ['x' => 5, 'y' => 10]
DA string 'x y'
What does extract(['a' => 1, 'b' => 2]) do?
ADeletes variables <code>$a</code> and <code>$b</code>
BCreates variables <code>$a = 1</code> and <code>$b = 2</code>
CCreates an array with keys 'a' and 'b'
DReturns an array [1, 2]
If you want to avoid overwriting existing variables when using extract(), which flag should you use?
AEXTR_OVERWRITE
BEXTR_IF_EXISTS
CEXTR_PREFIX_ALL
DEXTR_SKIP
Which function would you use to turn variables into an associative array?
Acompact()
Barray_keys()
Carray_merge()
Dextract()
What will happen if you call extract() on an empty array?
ANothing happens, no variables are created
BIt throws an error
CIt creates variables with null values
DIt deletes all existing variables
Explain how compact() and extract() work and how they can be used together.
Think about turning variables into arrays and back.
You got /4 concepts.
    What precautions should you take when using extract() in your code?
    Consider variable conflicts and safety.
    You got /4 concepts.

      Practice

      (1/5)
      1. What does the PHP function compact do?
      easy
      A. Creates an array from given variable names and their values
      B. Extracts variables from an array into the current symbol table
      C. Deletes variables from the current scope
      D. Converts an array into a JSON string

      Solution

      1. Step 1: Understand the purpose of compact

        The compact function takes variable names as strings and creates an associative array where keys are those names and values are the variables' values.
      2. Step 2: Differentiate from extract

        extract does the opposite by creating variables from array keys, so it is not the correct description for compact.
      3. Final Answer:

        Creates an array from given variable names and their values -> Option A
      4. Quick Check:

        compact = array from variables [OK]
      Hint: Remember: compact packs variables into an array [OK]
      Common Mistakes:
      • Confusing compact with extract
      • Thinking compact extracts variables
      • Assuming compact converts arrays to strings
      2. Which of the following is the correct syntax to use extract on an array $data?
      easy
      A. extract = $data;
      B. extract($data);
      C. extract->$data();
      D. extract($data[]);

      Solution

      1. Step 1: Recall the function call syntax

        In PHP, functions are called by their name followed by parentheses containing arguments. So extract($data); is the correct syntax.
      2. Step 2: Identify incorrect syntax

        Options B, C, and D misuse assignment, object operator, or array syntax, which are invalid for function calls.
      3. Final Answer:

        extract($data); -> Option B
      4. Quick Check:

        Function call syntax = extract($data); [OK]
      Hint: Use parentheses to call extract with array argument [OK]
      Common Mistakes:
      • Using assignment instead of function call
      • Using object operator (->) incorrectly
      • Adding brackets after variable name
      3. What is the output of the following PHP code?
      $name = "Alice";
      $age = 30;
      $arr = compact('name', 'age');
      print_r($arr);
      medium
      A. Array ( [Alice] => name [30] => age )
      B. Array ( [0] => name [1] => age )
      C. Error: Undefined variables
      D. Array ( [name] => Alice [age] => 30 )

      Solution

      1. Step 1: Understand compact behavior

        The compact function creates an array where keys are the variable names as strings and values are the current values of those variables.
      2. Step 2: Apply to given variables

        Variables $name and $age have values "Alice" and 30, so the array will be ['name' => 'Alice', 'age' => 30].
      3. Final Answer:

        Array ( [name] => Alice [age] => 30 ) -> Option D
      4. Quick Check:

        compact('name','age') = array with keys and values [OK]
      Hint: compact creates array with variable names as keys [OK]
      Common Mistakes:
      • Thinking compact returns variable values as keys
      • Expecting numeric keys instead of variable names
      • Assuming compact prints variables directly
      4. Identify the error in this PHP code snippet:
      $data = ['color' => 'red', 'size' => 'large'];
      extract($data);
      echo $colour;
      medium
      A. Variable name mismatch: $colour vs 'color' key
      B. extract() cannot be used on associative arrays
      C. Missing semicolon after extract()
      D. echo cannot print variables created by extract()

      Solution

      1. Step 1: Check variable names created by extract()

        The extract function creates variables named exactly as the array keys, so it creates $color and $size.
      2. Step 2: Compare echoed variable name

        The code tries to echo $colour which is different from $color, causing an undefined variable notice.
      3. Final Answer:

        Variable name mismatch: $colour vs 'color' key -> Option A
      4. Quick Check:

        extract keys = variable names; spelling must match [OK]
      Hint: Check spelling of variable names after extract [OK]
      Common Mistakes:
      • Assuming extract changes variable names
      • Thinking extract only works on indexed arrays
      • Ignoring PHP notices for undefined variables
      5. Given the array $info = ['name' => 'Bob', 'age' => 25, 'city' => 'Paris', 'age' => 30];, what will be the result of extract($info); echo $age;?
      hard
      A. 25
      B. Error: Duplicate keys in array
      C. 30
      D. Undefined variable error

      Solution

      1. Step 1: Understand PHP array key behavior

        When an array has duplicate keys, the last value overwrites previous ones. Here, 'age' appears twice with values 25 and 30, so 30 is kept.
      2. Step 2: Apply extract() and echo

        Extract creates variables from keys, so $age will be 30, the last value. Echoing $age prints 30.
      3. Final Answer:

        30 -> Option C
      4. Quick Check:

        Duplicate keys keep last value; extract uses that [OK]
      Hint: Last duplicate key value is used in arrays [OK]
      Common Mistakes:
      • Expecting first duplicate key value to be used
      • Thinking extract throws error on duplicates
      • Assuming undefined variable error due to duplicates
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