Variable naming rules in PHP - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare a variable named $name with the value "John".

PHP

<?php
$[1] = "John";
?>

Drag options to blanks, or click blank then click option'

Aname!

B1name

Cmy-name

Dname

Attempts:

3 left

💡 Hint

Common Mistakes

Starting variable names with a number.

Using special characters like hyphens or exclamation marks in variable names.

In PHP, variable names must start with a letter or underscore and can contain letters, numbers, and underscores. $name is valid.

2fill in blank

medium

Complete the code to declare a variable named $user_age and assign it the value 30.

PHP

<?php
$[1] = 30;
?>

Drag options to blanks, or click blank then click option'

Auser_age

Buser-age

Cuser age

Duser.age

Attempts:

3 left

💡 Hint

Common Mistakes

Using hyphens or dots in variable names.

Including spaces in variable names.

Underscores are allowed in PHP variable names, so $user_age is valid.

3fill in blank

hard

Fix the error in the variable declaration to make it valid.

PHP

<?php
$[1] = "Hello";
?>

Drag options to blanks, or click blank then click option'

A_greeting

B2greeting

Cgreeting!

Dgreeting message

Attempts:

3 left

💡 Hint

Common Mistakes

Starting variable names with numbers.

Using spaces or special characters in variable names.

Variable names can start with an underscore and contain letters and numbers, so $_greeting is valid.

4fill in blank

hard

Fill both blanks to declare a variable named $totalCount and assign it the value 100.

PHP

<?php
$[1] = [2];
?>

Drag options to blanks, or click blank then click option'

AtotalCount

B100

Cone_hundred

DcountTotal

Attempts:

3 left

💡 Hint

Common Mistakes

Using invalid variable names with spaces or special characters.

Assigning numbers as strings when an integer is expected.

The variable name $totalCount is valid and assigning the integer 100 is correct.

5fill in blank

hard

Fill all three blanks to create an associative array with variable $person having keys name and age.

PHP

<?php
$[1] = [
    '[2]' => 'Alice',
    '[3]' => 25
];
?>

Drag options to blanks, or click blank then click option'

Aperson

Bname

Cage

Duser

Attempts:

3 left

💡 Hint

Common Mistakes

Using invalid variable names.

Using keys with spaces or special characters.

The variable $person holds an associative array with keys name and age, which are valid string keys.