The null coalescing operator helps you quickly choose a value that is not null. It makes your code shorter and easier to read when checking if something exists or has a value.
When you want to use a default value if a variable is not set or is null.
When reading user input that might be missing or empty.
When working with arrays or objects where some keys or properties might not exist.
When you want to avoid long if-else checks for null or undefined values.
Syntax
PHP
$value = $variable ?? $defaultValue;
The operator is written as two question marks: ??.
It returns the left value if it is set and not null; otherwise, it returns the right value.
Examples
If $userName is set and not null, $name gets its value; otherwise, it becomes 'Guest'.
PHP
$name = $userName ?? 'Guest';
Uses 18 as a default age if $inputAge is null or not set.
PHP
$age = $inputAge ?? 18;
Chooses the color from preferences if available; otherwise, defaults to 'blue'.
PHP
$color = $preferences['color'] ?? 'blue';
Sample Program
This program prints a greeting. Since $userInput is null, it prints the default message.
PHP
<?php
// Example using null coalescing operator
$userInput = null;
$default = 'Hello, friend!';
// Use ?? to pick user input if set and not null, else default
$message = $userInput ?? $default;
echo $message;
OutputSuccess
Important Notes
The null coalescing operator only checks for null or unset variables, not other falsey values like 0 or empty string.
You can chain multiple ?? operators to check several values in order.
Summary
The null coalescing operator ?? returns the first value that is set and not null.
It helps simplify code that needs default values.
Use it to avoid long if-else statements when checking for null or unset variables.
Practice
(1/5)
1. What does the null coalescing operator ?? do in PHP?
easy
A. Returns the first operand if it is not null, otherwise returns the second operand.
B. Returns true if both operands are null.
C. Checks if a variable is set and throws an error if not.
D. Assigns null to a variable if it is not already set.
Solution
Step 1: Understand the operator's purpose
The null coalescing operator ?? checks if the left value is null.
Step 2: Determine the returned value
If the left value is not null, it returns that; otherwise, it returns the right value.
Final Answer:
Returns the first operand if it is not null, otherwise returns the second operand. -> Option A
Quick Check:
Null coalescing operator returns first non-null value [OK]
Hint: Remember: returns first non-null value [OK]
Common Mistakes:
Thinking it returns true/false
Confusing it with the ternary operator
Assuming it throws errors if variable is unset
2. Which of the following is the correct syntax to use the null coalescing operator in PHP?
easy
A. $value = $a ??= $b;
B. $value = $a ?: $b;
C. $value = $a ? $b;
D. $value = $a ?? $b;
Solution
Step 1: Identify the null coalescing operator syntax
The operator is written as ?? between two expressions.
Step 2: Check each option
$value = $a ?? $b; uses $a ?? $b which is correct syntax. $value = $a ?: $b; uses the ternary shorthand, not null coalescing. $value = $a ? $b; is incomplete syntax. $value = $a ??= $b; uses ??= which is a different operator (null coalescing assignment).
Final Answer:
$value = $a ?? $b; -> Option D
Quick Check:
Correct null coalescing syntax uses ?? between values [OK]
Hint: Use ?? between two values for null coalescing [OK]
Common Mistakes:
Confusing ?? with ?: operator
Using incomplete or invalid syntax
Mixing null coalescing with assignment operator
3. What will be the output of the following PHP code?
$a = null; $b = 5; $c = $a ?? $b; echo $c;
medium
A. null
B. 0
C. 5
D. Error
Solution
Step 1: Evaluate the variables
$a is null, $b is 5.
Step 2: Apply null coalescing operator
$c = $a ?? $b means if $a is not null use $a, else use $b. Since $a is null, $c becomes 5.
Final Answer:
5 -> Option C
Quick Check:
Null coalescing returns 5 when left is null [OK]
Hint: If left is null, output right value [OK]
Common Mistakes:
Assuming output is null
Confusing with ternary operator behavior
Expecting error due to null variable
4. Identify the error in the following PHP code using the null coalescing operator:
$value = ?? 10;
medium
A. Missing left operand before ?? operator.
B. Missing semicolon at the end.
C. Using wrong operator, should be ?: instead of ??.
D. No error, code is correct.
Solution
Step 1: Analyze the operator usage
The null coalescing operator requires a left and right operand, like $a ?? $b.
Step 2: Identify the error in the code
The code has ?? 10 without a left operand before ??, which is invalid syntax.
Final Answer:
Missing left operand before ?? operator. -> Option A
Quick Check:
Null coalescing needs both operands [OK]
Hint: Both sides needed for ?? operator [OK]
Common Mistakes:
Leaving out left operand
Confusing ?? with ternary operator
Ignoring syntax errors
5. Given the array $data = ['name' => null, 'age' => 25];, which code snippet correctly assigns $result to the value of 'name' if it exists and is not null, otherwise to 'Unknown'?
hard
A. $result = $data['name'] ?? 'Unknown';
B. $result = isset($data['name']) ? $data['name'] : 'Unknown';
C. $result = $data['name'] ?: 'Unknown';
D. $result = $data['name'] ??= 'Unknown';
Solution
Step 1: Understand the difference between ?? and isset()
The null coalescing operator returns the right value if the left is null or not set. However, if the key exists with a null value, $data['name'] ?? 'Unknown' returns 'Unknown'.
Step 2: Check each option's behavior
$result = $data['name'] ?? 'Unknown'; returns 'Unknown' because 'name' is null. $result = isset($data['name']) ? $data['name'] : 'Unknown'; uses isset() which returns false if null, so it returns 'Unknown'. $result = $data['name'] ?: 'Unknown'; uses ?: which treats null as false, so returns 'Unknown'. $result = $data['name'] ??= 'Unknown'; uses ??= which assigns 'Unknown' to $data['name'] if null or unset, then returns it.
Step 3: Choose the best option for the requirement
The question asks to assign $result to 'name' if it exists and is not null, else 'Unknown'. Since 'name' exists but is null, only $result = isset($data['name']) ? $data['name'] : 'Unknown'; correctly checks existence and returns 'Unknown'. $result = $data['name'] ?? 'Unknown'; and C treat null as missing, $result = $data['name'] ??= 'Unknown'; modifies the array which is not asked.
Final Answer:
$result = isset($data['name']) ? $data['name'] : 'Unknown'; -> Option B
Quick Check:
Use isset() to check existence and null separately [OK]
Hint: Use isset() to check key exists and not null [OK]
Common Mistakes:
Assuming ?? checks key existence only
Using ??= which changes original array
Confusing ?: with ?? operator
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