PHP - Type HandlingWhat does the following PHP code do?$num = (int) "123";AConverts the string "123" to an integer 123BConverts the integer 123 to a stringCThrows a syntax errorDLeaves the variable as a stringCheck Answer
Step-by-Step SolutionSolution:Step 1: Identify the type casting operationThe code uses (int) before a string variable, which means it converts the string to an integer.Step 2: Understand the conversion resultThe string "123" becomes the integer 123 after casting.Final Answer:Converts the string "123" to an integer 123 -> Option AQuick Check:Type casting (int) converts string "123" to integer 123 [OK]Quick Trick: Casting (int) changes strings of digits to numbers [OK]Common Mistakes:Thinking it converts integer to stringExpecting a syntax errorAssuming the variable stays a string
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