[Solved] Identify the error in this PHP code snippet involving nested loops and break:for ($a = 0; $a — Ans: Using break 4; exceeds the number of nested loops | PHP

PHP - Loops

Identify the error in this PHP code snippet involving nested loops and break:

for ($a = 0; $a < 4; $a++) {
    for ($b = 0; $b < 4; $b++) {
        if ($b == 3) {
            break 4;
        }
        echo "$a$b ";
    }
}

AUsing break 4; exceeds the number of nested loops

BMissing semicolon after break statement

CIncorrect loop condition in inner loop

DEcho statement syntax error

Step-by-Step Solution

Solution:

Step 1: Count nested loops
There are 2 nested loops: outer and inner.
Step 2: Check break level
break 4; tries to break out of 4 loops, which do not exist.
Step 3: Understand PHP behavior
Using a break level greater than existing loops causes a fatal error.
Final Answer:
Using break 4; exceeds the number of nested loops -> Option A
Quick Check:
Break level must not exceed nested loop count [OK]

Quick Trick: Break level cannot be greater than nested loops count [OK]

Common Mistakes:

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