PHP - Type Handling
What will be the output of this PHP code?
$arr = [1, 2, 3];
echo gettype($arr);
What will be the output of this PHP code?
medium📝 Predict Output Q5 of 15
Step-by-Step Solution
Solution:
Step 1: Identify type of $arr
$arr is an array in PHP, created with square brackets.Step 2: gettype() returns "array" for arrays
So echo gettype($arr); outputs "array".Final Answer:
array -> Option DQuick Check:
gettype(array) = "array" [OK]
Quick Trick: Arrays return "array" string from gettype() [OK]
Common Mistakes:
- Thinking arrays are objects
- Expecting "list" or "collection"
- Confusing with JSON types
Master "Type Handling" in PHP
Want More Practice?
15+ quiz questions · All difficulty levels · Free
Free Signup - Practice All QuestionsMore PHP Quizzes