Which of the following is the correct way to include a variable $age inside a double-quoted string in PHP?

easy📝 Conceptual Q2 of 15

PHP - Output and String Handling

Which of the following is the correct way to include a variable $age inside a double-quoted string in PHP?

Aecho "I am $age years old.";

Becho 'I am $age years old.';

Cecho "I am {$age years old}.";

Decho "I am $age years old";

Step-by-Step Solution

Solution:

Step 1: Identify correct interpolation syntax
Variables inside double quotes are replaced by their values directly, so "$age" works.
Step 2: Check other options for errors
Single quotes do not interpolate; curly braces must enclose only variable names; missing semicolon is syntax error.
Final Answer:
echo "I am $age years old."; -> Option A
Quick Check:
Variable inside double quotes = interpolated [OK]

Quick Trick: Use double quotes and $variable for interpolation [OK]

Common Mistakes:

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