[Solved] Identify the problem in this PHP code: $arr = [1, 2, 3]; echo count($arr[3]); — Ans: Accessing undefined index before count() | PHP

PHP - Arrays

Identify the problem in this PHP code:

$arr = [1, 2, 3];
echo count($arr[3]);

Acount() cannot be used on array elements

BNo problem, code runs fine

CMissing semicolon after count()

DAccessing undefined index before count()

Step-by-Step Solution

Solution:

Step 1: Check array index usage
The code tries to access $arr[3], but the array has indexes 0,1,2 only.
Step 2: Understand error cause
Accessing $arr[3] returns NULL, so count(NULL) causes a warning or error.
Final Answer:
Accessing undefined index before count() -> Option D
Quick Check:
Access valid indexes before count() [OK]

Quick Trick: Check array indexes exist before counting elements [OK]

Common Mistakes:

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