[Solved] Find the error in this PHP code:$count = 10echo $count; — Ans: Missing semicolon after variable assignment | PHP

PHP - Variables and Data Types

Find the error in this PHP code:

$count = 10
echo $count;

AMissing semicolon after variable assignment

BVariable name should not start with $

Cecho cannot print variables

DVariable must be declared with var keyword

Step-by-Step Solution

Solution:

Step 1: Check syntax rules for PHP statements
Each statement must end with a semicolon (;).
Step 2: Identify missing semicolon
The first line lacks a semicolon after 10, causing a syntax error.
Final Answer:
Missing semicolon after variable assignment -> Option A
Quick Check:
Statements need ; at end [OK]

Quick Trick: Always end PHP statements with ; [OK]

Common Mistakes:

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