Identify the error in the following PHP code using the spaceship operator:

medium📝 Debug Q14 of 15

PHP - Operators

$a = 7;
$b = 3;
if ($a <=> $b) {
    echo 'a is greater';
}

AVariables $a and $b are not defined

BSpaceship operator cannot be used in if condition

CMissing semicolon after echo statement

DThe condition always evaluates to true except when values are equal

Step-by-Step Solution

Solution:

Step 1: Understand spaceship operator in if condition
The operator returns -1, 0, or 1. In PHP, 0 is false, others are true.
Step 2: Analyze the condition with $a=7 and $b=3
Since 7 > 3, it returns 1, so condition is true and echo runs.
Final Answer:
The condition always evaluates to true except when values are equal -> Option D
Quick Check:
Non-zero spaceship result is true in if [OK]

Quick Trick: Spaceship returns 0 (false) only if values equal [OK]

Common Mistakes:

Master "Operators" in PHP

9 interactive learning modes - each teaches the same concept differently

Want More Practice?

15+ quiz questions · All difficulty levels · Free

More PHP Quizzes