[Solved] Identify the error in this PHP code snippet:$var = nullif ($var === null) { echo 'Null value';} — Ans: Missing semicolon after assignment | PHP

PHP - Variables and Data Types

Identify the error in this PHP code snippet:

$var = null
if ($var === null) {
    echo 'Null value';
}

AIncorrect comparison operator

BMissing semicolon after assignment

CNull cannot be assigned to variables

DEcho statement syntax error

Step-by-Step Solution

Solution:

Step 1: Check syntax of assignment line
The line $var = null is missing a semicolon at the end, which is required in PHP.
Step 2: Verify other parts of the code
The comparison and echo statements are correct and valid.
Final Answer:
Missing semicolon after assignment -> Option B
Quick Check:
Every statement needs ; in PHP [OK]

Quick Trick: Check for missing semicolons after statements [OK]

Common Mistakes:

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