[Solved] What happens if you modify the array inside a foreach loop in PHP? For example:$arr = [1, 2, 3]; foreach ($arr as &$val) { $val *= 2; } print_r($arr); | PHP

PHP - Loops

What happens if you modify the array inside a foreach loop in PHP? For example:

$arr = [1, 2, 3];
foreach ($arr as &$val) {
  $val *= 2;
}
print_r($arr);

AThe original array values are doubled because foreach uses references.

BThe array remains unchanged because foreach copies values.

CThe code causes a syntax error due to & in foreach.

DOnly the last element is doubled.

Step-by-Step Solution

Solution:

Step 1: Understand foreach with reference
Using & before the loop variable means it references original array elements.
Step 2: Effect of modifying referenced values
Changes inside the loop affect the original array, doubling each value.
Final Answer:
The original array values are doubled because foreach uses references. -> Option A
Quick Check:
Using & in foreach modifies original array [OK]

Quick Trick: Use & to modify original array elements inside foreach [OK]

Common Mistakes:

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