[Solved] What will be the output of this PHP code?function add($a, $b) { return $a + $b; echo "Done"; } $result = add(3, 4); echo $result; | PHP

PHP - Functions

What will be the output of this PHP code?

function add($a, $b) {
  return $a + $b;
  echo "Done";
}
$result = add(3, 4);
echo $result;

A7

BDone7

C7Done

DError

Step-by-Step Solution

Solution:

Step 1: Understand return stops function execution
The return $a + $b; sends back 7 and stops the function, so echo "Done"; is never run.
Step 2: Output the returned value
The variable $result gets 7, and echo $result; prints 7 only.
Final Answer:
7 -> Option A
Quick Check:
Return stops function, only 7 printed [OK]

Quick Trick: Code after return inside function does not run [OK]

Common Mistakes:

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